Karamba3D

Comment

Comment by Leonardo on January 7, 2015 at 3:56pm

Hi Clemens,

I need your help! I have a very simple curved geometry, like an arch, composed by several beams. This is a not funicular geometry and there are huge bending moments. I do not understand:

1) if the Cross Section Optimization component takes into account buckling for members in bending and axial compression (6.3.3 - Eurocode 3).  

2) if the buckling length corresponds to each beam or to the length of the whole arch or to the distance between supports (local or global buckling.

If instead of an arch, there is a more complex structure, i.e. an arch bridge with tendons and deck, what is the buckling length of the arch adopted by the Cross Section Optimization component?

Many thanks,

Leonardo

Comment by Llordella Patricio on October 22, 2014 at 12:40pm

Dear clemens

Thanks for the help, I just created a topic discussion and add any comments that we have done so far.

Best regards

Patricio

Comment by Karamba3D on October 21, 2014 at 12:00pm

Dear Patricio,

try to increase the number of shell elements. As mentioned in the manual they are linear elements. A mesh that is too coarse leads to a response which is stiffer than the real structure. 

Best,

Clemens

P.S.: Could you please open a new discussion on the topic? These discussions are easier to find and follow for other people who face a similar problem.

Comment by Llordella Patricio on October 15, 2014 at 3:41pm

Dear clemens

I was doing a rough estimate of the deformation, and I can not achieve the same result with Karamba.
When I make a rough estimate of the result with Karamba beams and mine are very similar, I think the problem is when I connect the shell, because there are no similar results.

I sent the GH file, and an image of the calculation

The structure is concrete
The result I get is 0.58cm

thank you

Patricio

15-10-14%20Example.gh

Comment by Llordella Patricio on October 10, 2014 at 8:43am

Perfect, that is just what I needed, thank you very much for your help, I'll keep working and any questions write again, it is very useful for students to understand the structural performance.

best regards

Patricio

Comment by Karamba3D on October 9, 2014 at 10:46am

You could use the 'Mesh Edges'-component to retrieve the naked edges and turn them into beams - see attached file: 91014Example1_cp.gh

Best regards,

Clemens

Comment by Llordella Patricio on October 9, 2014 at 8:35am

Hello, succeeds in creating the mesh to the slab, and built the beam segment, but when I see the deformations are not expected because the beam is deformed as the slab.

Thanks for the help

PS: maybe I'm using the program for a type of structure that is not the most appropriate, as I saw in the examples of other structures. But this type of structure is that students taught

best regards

Patricio

9-10-14%20Example%201.gh

Comment by Karamba3D on October 8, 2014 at 11:59am

Hi Patricio,
if you flatten the 'Elem'-input at the 'Assemble'-component the definition works. The triangular shell elements have linear displacement interpolations whereas the beam deflections are exact. In order to get correct results you should refine the shell mesh.

Best, Clemens

Comment by Llordella Patricio on October 8, 2014 at 8:30am

Hi Clemens,

I did what you suggested but now assemble element doesn´t work properly. Could you please tell me how to fix it? Thanks in advance, Patricio

8-10-14losa%20cadena.gh

Comment by Karamba3D on October 7, 2014 at 11:27pm

Hello Patricio, divide the beams in such a way that each boundary vertex of the shell becomes an endpoint of a beam segment.

Best, Clemens

• ‹ Previous
• 1
• …
• 11
• 12
• 13
• 14
• 15
• …
• 28
• Next ›
• Page