ems in the same way. Lofting was particularly difficult, you had to have a separate loft component for every lofted surface that you wanted to generate because the component would/could only see one large list of inputs. Then came along the data structures in GH v0.6 which allowed for the segregation of multiple input sets.
If you go to Section 8: The Garden of Forking Paths of the Grasshopper Primer 2nd Edition you will find the image above describing the storing of data.
Here you will notice a similarity between the path {0;0;0;0}(N=6) and the pathmapper Mask {A;B;C;D}(i). A is a placeholder for all of the first Branch structures (in this case just 0). B is a place holder for all the second branch structures possibly either 0, 1 or 2 in this case. And so forth.
(i) is a place holder for the index of N. If you think of it like a for loop the i plays the same role. For the example {A;B;C;D}(i) --> {i\3}
{0;0;0;0}(0) --> {0\3} = {0}
{0;0;0;0}(1) --> {1\3} = {0}
{0;0;0;0}(2) --> {2\3} = {0}
{0;0;0;0}(3) --> {3\3} = {1}
{0;0;0;0}(4) --> {4\3} = {1}
{0;0;0;0}(5) --> {5\3} = {1}
{0;0;0;1}(0) --> {0\3} = {0}
{0;0;0;1}(1) --> {1\3} = {0}
{0;0;0;1}(2) --> {2\3} = {0}
{0;0;0;1}(3) --> {3\3} = {1}
{0;0;0;1}(4) --> {4\3} = {1}
{0;0;0;1}(5) --> {5\3} = {1}
{0;0;0;1}(6) --> {6\3} = {2}
{0;0;0;1}(7) --> {7\3} = {2}
{0;0;0;1}(8) --> {8\3} = {2}
...
{0;2;1;1}(8) --> {8\3} = {2}
I'm not entirely sure why you want to do this particular exercise but it goes some way towards describing the process.
The reason for the tidy up: every time the data stream passes through a component that influences the path structure it adds a branch. This can get very unwieldy if you let it go to far. some times I've ended up with structures like {0;0;1;0;0;0;3;0;0;0;14}(N=1) and by remapping the structure to {A;B;C} you get {0;0;1}(N=15) and is much neater to deal with.
If you ever need to see what the structure is there is a component called Param Viewer on the first Tab Param>Special Icon is a tree. It has two modes text and visual double click to switch between the two.
Have a look at this example of three scenarios in three situations to see how the data structure changes depending on what components are doing.
…
oxes in the most efficient way within boundaries of object and follow the following constraints. The Goal: To fit 125 boxes in the most efficient way inside the total area. Starting Variables: (1) 40% of the Boxes need to be between 60 and 85MSQ. (2) 40% of the boxes need to be between 86 and 110MSQ.
(3) 20% of the boxes need to be between 111 and 125mSQ. The breakdown doesn’t have to be exact to give the script some flexibility. Meaning you can have 41% +39% +20% = 100%.
Constraints:
1. A total MAXIMUM area of approximately 1600M per layer.
2. A maximum of 8 layers for a total of 12,800M per layer. Optimization can make as little or as many as 8 layers vertical to accommodate all boxes. So if script can achieve with 3 levels great. If needed all 8 levels, that's fine too. However, pay attention to next constraint (#3).
3. Approximately 15% of that space on each layer is off limits. (internal area) (blue area in example script) and the shape of the boundary cannot be modified to accommodate box design resulting in jagged lines for the internal area.
4. All generated squares/rectangles must have at least 3m touching an outside border (The Green lines).
5. All boxes must also be touching minimum 1M of border of the blue line.
6. If the boxes generated go outside the green boundary, they must be fillet to maintain the straight lines of the green boundaries.
7. Get as many of the boxes as possible a view towards the dots.
Could any one provide me a method or a way to start, if there are any useful links, please share with me. Thank you!…
Boxes in the most efficient way within boundaries of object and follow the following constraints.
The Goal: To fit 125 boxes in the most efficient way inside the total area. Starting Variables:
(1) 40% of the Boxes need to be between 60 and 85MSQ. (2) 40% of the boxes need to be between 86 and 110MSQ.
(3) 20% of the boxes need to be between 111 and 125mSQ. The breakdown doesn’t have to be exact to give the script some flexibility. Meaning you can have 41% +39% +20% = 100%.
Constraints:
1. A total MAXIMUM area of approximately 1600M per layer.
2. A maximum of 8 layers for a total of 12,800M per layer. Optimization can make as little or as many as 8 layers vertical to accommodate all boxes. So if script can achieve with 3 levels great. If needed all 8 levels, that's fine too. However, pay attention to next constraint (#3).
3. Approximately 15% of that space on each layer is off limits. (internal area) (blue area in example script) and the shape of the boundary cannot be modified to accommodate box design resulting in jagged lines for the internal area.
4. All generated squares/rectangles must have at least 3m touching an outside border (The Green lines).
5. All boxes must also be touching minimum 1M of border of the blue line.
6. If the boxes generated go outside the green boundary, they must be fillet to maintain the straight lines of the green boundaries.
7. Get as many of the boxes as possible a view towards the dots.
Could any one provide me a method or a way to start, if there are any useful links, please share with me. Thank you!
…
re is my problem... I need to arrange Boxes in the most efficient way within boundaries of object and follow the following constraints.
The Goal: To fit 125 boxes in the most efficient way inside the total area. Starting Variables:
(1) 40% of the Boxes need to be between 60 and 85MSQ. (2) 40% of the boxes need to be between 86 and 110MSQ.
(3) 20% of the boxes need to be between 111 and 125mSQ. The breakdown doesn’t have to be exact to give the script some flexibility. Meaning you can have 41% +39% +20% = 100%.
Constraints:
1. A total MAXIMUM area of approximately 1600M per layer.
2. A maximum of 8 layers for a total of 12,800M per layer. Optimization can make as little or as many as 8 layers vertical to accommodate all boxes. So if script can achieve with 3 levels great. If needed all 8 levels, that's fine too. However, pay attention to next constraint (#3).
3. Approximately 15% of that space on each layer is off limits. (internal area) (blue area in example script) and the shape of the boundary cannot be modified to accommodate box design resulting in jagged lines for the internal area.
4. All generated squares/rectangles must have at least 3m touching an outside border (The Green lines).
5. All boxes must also be touching minimum 1M of border of the blue line.
6. If the boxes generated go outside the green boundary, they must be fillet to maintain the straight lines of the green boundaries.
7. Get as many of the boxes as possible a view towards the dots.
Could any one provide me a method or a way to start, if there are any useful links, please share with me. Thank you!
…
t, let's talk about randomness. Randomness is a problem in computing because digital computers are deterministic. If you give them the exact same instructions they always end up with the exact same result. It turns out to be mathematically impossible to generate true random numbers using a digital computer, but it is fairly easy to generate pseudo-random numbers. This is actually not bad news as pseudo-random numbers -unlike real random numbers- can be generated again and again and you'll end up with the same random numbers every time. Being able to get the same random numbers on demand increases the reliability of these number sequences which in turn makes them easier to use.
Pseudo-random numbers are numbers that have certain characteristics. Note that when we talk about random numbers we are really talking about numbers. Plural. It's easy to generate only a single one, as xkcd so eloquently put it:
So what are these characteristics that define pseudo-randomness? Without being actually correct, I can sum them up as follows:
The sequence of generated numbers should never repeat itself*
The numbers in the sequence ought to be spread evenly across the numeric domain**
There are a lot of different algorithms out there, some better than others, some faster than others, some solving very specific problems while others are more generic. The generator used in Grasshopper is the standard Microsoft .NET Random, based on Donald Knuth's subtractive algorithm.
So let's imagine we want random integers between 0 and 10. What would a bad random sequence look like?
3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 (about as bad as it gets)
0 1 2 3 4 5 6 7 8 9 0 1 2 3 4 5 6 7 8 9 (not random at all)
1 3 2 5 3 9 1 2 4 2 5 1 1 2 8 1 5 2 3 4 (too many low numbers)
2 8 4 6 0 9 8 2 4 8 6 4 2 2 5 1 4 8 6 2 (too many even numbers)
So what about good sequences? Well, here's a few:
6 9 1 2 0 4 2 8 5 7 2 9 1 9 2 5 3 1 9 2 (sure, why not)
6 2 5 3 4 1 9 7 8 0 2 1 6 4 5 8 9 5 0 9 (looks about right)
1 8 5 2 3 4 5 7 9 5 2 1 0 2 1 0 9 7 6 4 (I suppose)
9 0 6 4 8 3 1 5 2 7 6 1 4 6 0 1 9 7 5 6 (whatever)
There are a lot of valid pseudo-random sequences. (Seriously, loads). So even if we have a good pseudo-random generator we may be given a random sequence that isn't entirely to our liking. The shorter the sequence we need, the more likely it is that statistical aberrations invalidate that particular sequence for us. What we need is some control over the generator so we don't just get a repeatable sequence, but a repeatable sequence we actually like.
Enter seed values. The random generator requires a seed value before it can generate a random sequence. These seed values are always integers, and they can be any valid 32-bit integer. Every unique seed value results in the same sequence. Every time.
Unfortunately there is no clear relationship between seeds and sequences. Changing the seed value from 5 to 6 will result in a completely difference random sequence, and two sequences that are very similar may well have to wildly different seeds. There is therefore no way to guess a good seed value, it is completely trial-and-error. Also because of this extremely discontinuous nature, you cannot use tools like Galapagos to optimize a seed value.
If you are looking for a pseudo-random sequence which has custom characteristics, you may well end up having to write your own generator algorithm. Ask questions about this on the Grasshopper main forum or the VB/C# forum.
Conclusion: Seed values are integers that define the exact sequence of pseudo-random numbers, but there's no way of knowing ahead of time what sequence it will be and there's no way of tweaking a sequence by slightly changing the seed. Even the tiniest change in seed value will result in a radically different random sequence.
--
David Rutten
david@mcneel.com
Poprad, Slovakia
* This is not actually possible. A finite amount of numbers always repeats itself eventually.
** This should only be true for long enough sequences, short sequences are allowed to cluster their values somewhat.
Interesting links for further reading:
Coding Horror: Computers are Louse Random Number Generators
StackOverflow: When do random numbers start repeating?…
Added by David Rutten at 9:52am on October 20, 2012
the one-but-last list [4]. After running out of the n- items avalaible it should continue with the second item of list 0 and so on for all items on all the lists.
Intput, six lists of 30 items each
[0] (n=30)
[1] (n=30)
[2] (n=30)
[3] (n=30)
[4] (n=30)
[5] (n=30)
Output, 18 lists of 10 items each
[0],i=0;[5],i=4; [4],i=7;...
[0],i=1;[5],i=5; [4],i=8;...
...
[5],i=1;[4],i=5; [3],i=0;...
I thought perhaps the weave component or the relative tree item component but didn't manage to figure out how to compose the mask. I couldn't find much on how to use these. I guess it should wrap the lists, but not the items.
Any help would be greatly appreciated.…
Added by Thorsten Lang at 2:27am on January 24, 2011
number of divisions on that curve as in the defintion (i.e. by 4). The offset in the def is slightly different and should cull two or three more curves as in the lists that show my aim below.
Basically I want to look into each branch of the groups of points from each closed curve . Marking in a list whether it contains a one or a zero (0= outside 1 = coincidents).
{0;0}0. 21. 22. 23. 2 {0;1} 0. 01. 22. 03. 2 {0;2}0. 01. 02. 03. 0 {0;3}0. 21. 22. 23. 2 {0;4}0. 21. 22. 23. 2 {0;5}0. 21. 22. 23. 2 {0;6}0. 01. 22. 23. 1 {0;7}0. 21. 22. 03. 0 {0;8}0. 21. 22. 23. 2 {0;9}0. 21. 22. 23. 2 {0;10}0. 21. 22. 23. 2 {0;11}0. 21. 22. 23. 2 {0;12}0. 21. 22. 23. 2 {0;13}0. 01. 22. 23. 0 {0;14}0. 21. 22. 23. 2
I want to create a list from these points. That marks each curve that pokes out, in a cull pattern as such:
20022210222202
Using a 1 where there are co-incidents in the curve points and the boundary. A 2 for true (outside points) and a 0 for containment. So I might be able to use the 1 in future developments - however if a true false list is easiest I can live with that.
So could I use F(x) function? - to look for 0 or 1's in each bunch of points and thus list as such for a cull pattern? or will Path mapper help me here? Or can I rely on simply grafting and splitting??
I am usure of the neatest solution and would love to learn. Hope you can direct me.rgrds
J.…
0, 5, 10, 15, 20
1, 6, 11, 16, 21
2, 7, 12, 17, 22
3, 8, 13, 18, 23
4, 9, 14, 19, 24
and if i'm here is because i'm not able... :)
can you help me?
thank you
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