the curves on surface issue it's solved seting flatten to the surface control point output. Still didnt know how to group points like:
1;1, 2;2, 3;3.....
1;2, 2;3, 3;4....
1;3, 2;4, 3;5...
....
{1;1;4}{1;1;5}{1;2;0}{1;2;1}{1;2;2}{1;2;3}{1;2;4}{1;2;5}{1;3;0}{1;3;1}{1;3;2}{1;3;3}{1;3;4}{1;3;5}
etc...
and I want to format as a text it so it replaces the innermost branch with a letter so {0;0;1} would read A-0-1. I am able to replace all the symbols using replace text but am no sure if there's a way to convert a number to a letter.…
Added by Ryan Whitby at 12:40pm on February 3, 2015
e possible to change the component definition making possible to customize the number of outputs.Now Dispatch moves "true" values to A and "False" values to B
INPUT:
L (List to work on) -> 1, 2, 3, 4, 5, 6, 7, 8
D (Dispatch Pattern) -> True, False
OUTPUT:
A (List) -> 1, 3, 5, 7
B (List) -> 2, 4, 6, 8
Could it be possible/useful to modify it so it could dispatch items to several outputs, like:
INPUT:
L (List to work on) -> 1, 2, 3, 4, 5, 6, 7, 8, 9, 0
D (Dispatch Pattern) -> A, B, C
OUTPUT:
A (List) -> 1, 4, 7, 0
B (List) -> 2, 5, 8
C (List) -> 3, 6, 9
maybe I'm missing something and there's already a component with this function... I have been searching on the forum for half afternoon, but can't find anything about it!
Thank you!…
number of divisions on that curve as in the defintion (i.e. by 4). The offset in the def is slightly different and should cull two or three more curves as in the lists that show my aim below.
Basically I want to look into each branch of the groups of points from each closed curve . Marking in a list whether it contains a one or a zero (0= outside 1 = coincidents).
{0;0}0. 21. 22. 23. 2 {0;1} 0. 01. 22. 03. 2 {0;2}0. 01. 02. 03. 0 {0;3}0. 21. 22. 23. 2 {0;4}0. 21. 22. 23. 2 {0;5}0. 21. 22. 23. 2 {0;6}0. 01. 22. 23. 1 {0;7}0. 21. 22. 03. 0 {0;8}0. 21. 22. 23. 2 {0;9}0. 21. 22. 23. 2 {0;10}0. 21. 22. 23. 2 {0;11}0. 21. 22. 23. 2 {0;12}0. 21. 22. 23. 2 {0;13}0. 01. 22. 23. 0 {0;14}0. 21. 22. 23. 2
I want to create a list from these points. That marks each curve that pokes out, in a cull pattern as such:
20022210222202
Using a 1 where there are co-incidents in the curve points and the boundary. A 2 for true (outside points) and a 0 for containment. So I might be able to use the 1 in future developments - however if a true false list is easiest I can live with that.
So could I use F(x) function? - to look for 0 or 1's in each bunch of points and thus list as such for a cull pattern? or will Path mapper help me here? Or can I rely on simply grafting and splitting??
I am usure of the neatest solution and would love to learn. Hope you can direct me.rgrds
J.…
E.g.:
0 2 (A) = 2
1 2+4 (A+B) = 6 (AB)
2 6+4 (AB+C) = 10 (ABC)
3 10+6 (ABC+D) = 16 (ABCD)
etc.
Into a new list numbers:
{2,6,10,16, etc} that adding the previous number with the next number.
Thanks,
daniel
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