algorithmic modeling for Rhino
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- Comment on: Topic 'Divide list by item count'
- ts, a value for each point.This script is wrinting in C#, not C++. And of course, can be done with standard components, perhaps someone else help you with that.…
- Added by Daniel González Abalde at 5:46am on May 15, 2015
- Comment on: Topic 'divide in branches'
- that's actually 5 branches of 4 items. so you need: {A;B;C} --> {0;C\5;C%5} --- {0;0;19} --> {0;19\5;19%5} = {0;3;4}
- Added by Danny Boyes at 11:44am on June 25, 2011
- Comment on: Video 'Structural Element Regulation Study 02'
- ，记住，看一次和看两次的效果是完全不一样的，要懂得顺序渐进，很多分析方法都是建立在基础的方法上的。…
- Added by naasaki at 3:11pm on April 26, 2021
- Comment on: Topic 'brep volume is off by a factor of 8'
- It would appear that GH is doubling you inputs. 192*3*7=4032
- Added by Danny Boyes at 5:54pm on February 8, 2011
- Blog Post: Isolux curves for sky
Hallo Community,
Is there a plugin or a simple formula where i can insert the weather data (Global Illuminances) into a matrix and produce an isolux curve for sky?
The datas…
- Added by nass at 1:36am on May 14, 2017
- Topic: sum the first x elemente of a list of numbers
- 1+2+3+4+5+6 = 21 1+2+3+4+5+6+7 = 28 1+2+3+4+5+6+7+8 = 36 1+2+3+4+5+6+7+8+9 = 45 Is there a tool, that can do me that job? How do I get this List {1,3,6,10,15,21,28,36,45}?…
- Added by Ahmed Hossam at 2:19pm on September 22, 2013
- Topic: clustering neighbor elements
- different sets, but they are spread all over the place. I would be happy 4 Your help. Best. Lorcan…
- Added by Lorcan Koethe at 1:51pm on November 19, 2009
- Blog Post: RGSS(rhino & grasshopper study session)TOKYO #3
- Added by Yusuke Oono at 8:26pm on July 28, 2009
- Comment on: Topic 'data list manipulation'
- ep is to understan the logics of what you want to do, in your case, build 4 point surfaces (u also need to know the right direction to build the surfaces). Then you can write an hipotetic list (by hand in a paper) of what you want. In your case the list was (0, 1, 3, 2) (2, 3, 5, 4) (4, 5, 7, 6), etc... if you can imagine building 2 lists, each one with the sequences (0, 2, 4, 6, etcc) and (1, 3, 5, 7, etc..) then you can manage with shift and graft to finally have four lists. A( 0 1 2 3 ...) B (1 3 5 etc..) C(3 5 7 etc..) D (2 4 6 etc..). And to achieve the 2 first lists, you need to get the odd and the pair numbers. The cull pattern does that amazingy well. With a pattern True-False you get de pair numbers, and with the False-True pattern you get de odd numbers. Hope it was clear enough…
- Added by Pep Tornabell at 5:32am on November 19, 2009
- Topic: Recurrence addition to any number
- .. Please help, hope this make sense, Thank you all!…
- Added by bayupu at 12:21am on January 19, 2013
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