Search Results - 福彩3天齐网首页正版保真『0TBH·COM』福彩三d试机号码开机号码2023年3月19日7时42分22秒.H5c2a3.kcssaaksa.com

Topic: Dispatch component implementation: e possible to change the component definition making possible to customize the number of outputs.Now Dispatch moves "true" values to A and "False" values to B INPUT: L (List to work on) -> 1, 2, 3, 4, 5, 6, 7, 8 D (Dispatch Pattern) -> True, False OUTPUT: A (List) -> 1, 3, 5, 7 B (List) -> 2, 4, 6, 8 Could it be possible/useful to modify it so it could dispatch items to several outputs, like: INPUT: L (List to work on) -> 1, 2, 3, 4, 5, 6, 7, 8, 9, 0 D (Dispatch Pattern) -> A, B, C OUTPUT: A (List) -> 1, 4, 7, 0 B (List) -> 2, 5, 8 C (List) -> 3, 6, 9 maybe I'm missing something and there's already a component with this function... I have been searching on the forum for half afternoon, but can't find anything about it! Thank you!…; Added by Ale Inno at 9:21am on March 18, 2014

Comment on: Topic 'Specific results(outputs) for specific inputs?': 13 5 15 6 17 7 ... … But it seems I have not been clear: the input values (3,5,7,9,11,13) should be presented in the way of "number slider" parameter. So by increasing the value of the slider from minimum 3, to 5, 7, 9, 13, 15, 17... I should get an output numbers of 0,1,3,4,5,6,7... So I if choose value 3 on the input "number slider", on the other end, I want 0 as an output. Or if I choose value 5 on the input "number slider", I want 1 as an output, and so on. Is this possible?…; Added by djordje at 6:37pm on August 5, 2011

Topic: shifting number: shift. I realize I can use 'replace branch' but I do not have an available mask to utilize. I have simplified the problem to its simplest form so my question is understandable, however, the tree I am trying perform this operation on is a much larger 3 digit path address. {1;3;2} {2;3;4} {3;5;4} {4;3;7} Change the above list to the list below. {0;3;2} {1;3;4} {2;5:4} {3;3;7} I wish for a more robust arsenal of branch manipulation components. Most of the things I need to do are possible with the existing components, however, many operations take several components to perform even simple manipulations. Since branch/path manipulation is so integral to using GH successfully, it seems the GH community would be well served by enhancing the available path manipulation components. Thanks, Stan …; Added by Stan Carroll at 2:18pm on July 13, 2011

Comment on: Photo 'radiolarian inside': es of the lines 4. Catmull Clark subdivision 5. renderd with Artlantis…; Added by Csiby Zsolt at 2:07am on May 13, 2011

Comment on: Topic 'There is no Eigen plug': Version=1.0.0.0, Culture=neutral, PublicKeyToken=null”所使用的“RhinoCommon, Version=5.1.30000.12, Culture=neutral, PublicKeyToken=552281e97c755530”版本高于所引用的程序集“RhinoCommon, Version=5.1.30000.10, Culture=neutral, PublicKeyToken=552281e97c755530”的版本…; Added by 超李 to Millipede at 2:31am on April 2, 2014

Comment on: Topic 'Reordering branches by sorting the length of points connection': ;4}that like original tree structure?? …; Added by Tommy Su at 8:01am on May 3, 2017

Event: Grasshopper Basics: o Grasshopper and Rhino.Schedule: Rhinoceros1. NURBS and Mesh geometries.2. Complex geometries.3. GH to Rhinoceros workflow.Grasshopper1. Introduction to parametric design2. Parameters and components.3. Math and logics.4. 2D and 3D modeling.5. Simple definition6. Application to typical deisgn problems.SoftwareRhino + GrasshopperVenueParametric Support, Hardenbergstrasse 38, BerlinFee[Early Bird] 400 eur + VAT (until 11/11)[Regular] 420 eur + VAT[Student] 300 eurMore:hello@parametric.support…; Added by Judyta Cichocka at 4:32am on November 1, 2017

Topic: Get all vertices in each subgraph (for disjoint graph): {4}-0;3 {5}-6;7 {6}-5;7 {7}-5;6 Here it can be shown that there are two subgraphs containing 0,1,2,3,4 and 5,6,7. How can I use spiderweb (either using scripting or the components) to give me this result when I have many more vertices?? Thanks, Sam…; Added by Sam Gregson to SpiderWeb at 3:49am on November 24, 2015

Topic: Managing Data in Python (Working with Vectors): lections import defaultdict example_list = [[1,2,4], [1,2,3], [3,4,3], [1,2,3], [5,7,1], [3,4,3], [5,7,1], [1,2,4], [9,4,9], [9,3,9], [9,4,9]] d = defaultdict(list) for item in example_list: d[tuple(item)].append(item) groupedlist = sorted(d[x] for x in d) print groupedlist # Returns [[[1, 2, 3], [1, 2, 3]], [[1, 2, 4], [1, 2, 4]], [[3, 4, 3], [3, 4, 3]], [[5, 7, 1], [5, 7, 1]], [[9, 3, 9]], [[9, 4, 9], [9, 4, 9]]] ____________________________________________________ However working with python inside GH the code fails as (I'm assuming the id is included in the list ie. [<Rhino.Geometry.Point3d object at 0x0000000000000BD0 [1611664.12669822,2952929.94466619,5788.70761766478]>] If I print my object[0] i get just the vector, i.e [1611664.12669822,2952929.94466619,5788.70761766478] However if i append my object, (for i in xrange (len(X)... list.append(my object[x]) The id included!? [<Rhino.Geometry.Point3d object at 0x0000000000000BD0 [1611664.12669822,2952929.94466619,5788.70761766478]>] Perhaps I'm over complicating this and should just use GH to group objects with the same position... Also sometimes when getting vectors I receive long numbers such as.. 9.0122222900391e(10), and another times I don't.... Same file, script, geometry etc.. I'm quite a noobie in python for GH so any help or pointers are welcome... Thank you in advance! …; Added by Si at 10:52am on July 29, 2015