≈ 4.8 " as " x= 4.8 ± a ", do you know what is the min and max for "a"?
and second, i had tried the "round" function, but i faced problem with it too! for example:
if the input is a series as {0.0, 0.5, 1, 1.5, 2, 2.5, ...}
the output for Round(x, 0.5) is : {0, 0, 1, 2, 2, 2, 3, 4, 4, 4, 5, 6, 6, 6, ... }
and for Round(x, 2) the output is : {0.0, 0.5, 1, 1.5, 2, 2.5, ... }
i can't understand the logic that lies behind this function, i think
for Round(x, 0.5) the output must be {0.0, 0.5, 1, 1.5, 2, 2.5, 3, 3.5, 4, 4.5, ... }
and for Round(x, 2) it must be {0.0, 0.0, 2, 2, 2, 2, 4, 4, 4, 4, ... }
so, is there any problem with it, or I misendestood the logic ?…
{1;1;4}{1;1;5}{1;2;0}{1;2;1}{1;2;2}{1;2;3}{1;2;4}{1;2;5}{1;3;0}{1;3;1}{1;3;2}{1;3;3}{1;3;4}{1;3;5}
etc...
and I want to format as a text it so it replaces the innermost branch with a letter so {0;0;1} would read A-0-1. I am able to replace all the symbols using replace text but am no sure if there's a way to convert a number to a letter.…
Added by Ryan Whitby at 12:40pm on February 3, 2015
ents will do or which components will be available.
My problem arises because I want to obtain a list such as the following:
{{6, 5, 4, 3, 2, 1, 2, 3, 4, 5, 6}, {5, 6, 5, 4, 3, 2, 1, 2, 3, 4, 5}, {4, 5, 6, 5, 4, 3, 2, 1, 2, 3, 4}, {3, 4, 5, 6, 5, 4, 3, 2, 1, 2, 3}, {2, 3, 4, 5, 6, 5, 4, 3, 2, 1, 2}, {1, 2, 3, 4, 5, 6, 5, 4, 3, 2, 1}}
Which displayed as a matrix is:
If it were possible to combine GH operations (series, shift list, replace string...) with matrices I think it would be quite powerful. A matrix to list component like those available on scientific calculators, would then translate the matrix to list.
For me, matrices come in handy when dealing with surface patterns.
…
Added by Jesus Galvez at 6:46am on November 26, 2012
oning behind using the equality component to test for even numbers is flawed because of the data matching used by gh. It is testing like this:
0==0 True
2==1 False
4==2 False
6==3 False
etc
.............
Where as a Modulo 2 would work like this
0%2 = 0
1%2 = 1
2%2 = 0
3%2 = 1
4%2 = 0
5%2 = 1
6%2 = 0
7%2 = 1
8%2 = 0
9%2 = 1
......
Also I notice you have some errors in your expressions producing Nulls.
If you want it to be twice the value then you should have 2*D in the Expression and 10*D in the other
....
I attach a working version.…
the curves on surface issue it's solved seting flatten to the surface control point output. Still didnt know how to group points like:
1;1, 2;2, 3;3.....
1;2, 2;3, 3;4....
1;3, 2;4, 3;5...
....
operate on the data from your own components.
2) Put your 2D array data inside a Grasshopper.Kernel.Types.GH_ObjectWrapper instance, which is a class that can be used to transmit non-standard data through wires. Again, you'll only be able to use this from your own components.
3) Create your own data-type (implement IGH_Goo) as a 2D array.
4) (and my favourite) store your 2D data in a DataTree instead. All grasshopper data is stored in trees and it's possible to mimic a 2D array this way. For example, you could create a tree like this:
{0} N = 10
{1} N = 10
{2} N = 10
{3} N = 10
{4} N = 10
This would be analogous to a 2D matrix of 5 x 10.
--
David Rutten
david@mcneel.com
Poprad, Slovakia…
nts me this:
[[0], [0, 1], [0, 1, 2], [0, 1, 2, 3], [0, 1, 2, 3, 4], [0, 1, 2, 3, 4, 5], [0, 1, 2, 3, 4, 5, 6], [0, 1, 2, 3, 4, 5, 6, 7]]
this is what I wanted but how to convert this to tree in grasshopper?
In grasshopper I just get:
8x IronPython.Runtime.List…
ee 3)
{5}
0 15
{6}
0 16
And I want to place points at every possible combination of these coordinates, treating Tree 1 as X coordinates, Tree 2 as Y coordinates, and Tree 3 as Z coordinates. Also, I would like the list of points to be a tree with paths corresponding to the coordinates. Wouldn't it be nice if I could plug these trees into a Point XYZ, with a new "branch cross reference" method, and get the following result?
{0:3:5}
0 {10.0, 13.0, 15.0}
{0:3:6}
0 {10.0, 13.0, 16.0}
{0:4:5}
0 {10.0, 14.0, 15.0}
{0:4:6}
0 {10.0, 14.0, 16.0}
{1:3:5}
0 {11.0, 13.0, 15.0}
{1:3:6}
0 {11.0, 13.0, 16.0}
{1:4:5}
0 {11.0, 14.0, 15.0}
{1:4:6}
0 {11.0, 14.0, 16.0}
{2:3:5}
0 {12.0, 13.0, 15.0}
{2:3:6}
0 {12.0, 13.0, 16.0}
{2:4:5}
0 {12.0, 14.0, 15.0}
{2:4:6}
0 {12.0, 14.0, 16.0}
In this form of cross referencing, every combination of individual branches from the different lists is used as separate input, and the output for each combination is put onto a branch in the result whose path is the concatenation of the input branch paths used.…
Added by Andy Edwards at 7:03pm on November 3, 2009