earch Founder ofPachube.com and CEO of Connected Environments LtdBillie Faircloth KieranTimberlake Research DirectorCraig Schwitter & Gijs Libourel Buro Happold + Adaptive Building Initiative
Lisa Amini IBM's Smarter City Lab Dublin, LeaderMette Ramsgaard Thomsen Head of the Center for Information Technology and Architecture (CITA), Denmark
Additional speakers for the Talkshop day, including panel sessions and workshop reviews, will be posted to the website soon.
For more information, click here.
We are also very pleased to announce the launch of our new website at www.smartgeometry.org. It is a soft launch, meaning we are still adding new features to the page. However, Workshop Clusters are setting up their online homes for use before and during our workshops, and we'll be premiering all sorts of new features and content over the build-up to sg2011.
Come check it out to see how things are developing!…
. In this new branches list ,{2} contain the same items as {0} ,{3} contains the same items as {1} .
I hope I have made myself clear enough .Thanks for any help!!
…
an = True
For j As Integer = i + 1 To x.Count - 1
If round((x(i).x * 10 ^ 8 + x(i).y * 10 ^ 4 + x(i).z), 2) = round((x(j).x * 10 ^ 8 + x(j).y * 10 ^ 4 + x(j).z), 2) Then bol = False
Next
If bol Then ptlist.add(x(i))
Next
a = ptlist
I think someone posted a more appropiate way of doing it, similar to how the "seldup" command works. You can also run the seldup command in a script using app.RunScript("-seldup"), but its a bit messy since you have to bake the geometry first and select the resulting geometry all within the script.…
points 0, X-1, (2*x)-1, (3*X)-1, (4*X)-1, (5*X)-1 and then
1, X, (2*x), (3*X), (4*X), (5*X)
2, X+1, (2*x)+1, (3*X)+1, (4*X)+1, (5*X)+1
and so on till
5, X+4, (2*x)+4, (3*X)+4, (4*X)+4, (5*X)+4
How can I do this best?
Thanks,
Niels…
branches in each A's list of B's, or remove its ends etcso that if I want to remove the last B in every A{0;1},{0;2},{0;3},{0;4},{0;5},{0;6}{1;1},{1;2},{1;3},{1;4}{2;1},{2;2},{2;3},{2;4},{2;5}would become{0;1},{0;2},{0;3},{0;4},{0;5}
{1;1},{1;2},{1;3}
{2;1},{2;2},{2;3},{2;4}I guess the question is do I need to figure out the cull pattern- each B may have different lengths...…
7 x 2 lines.{0,0} to {5,16} N=2
I want to intersect each pair of the first 17 pairs of lines with the first pair of curves,
each pair of the second 17 pairs of lines with the second pair of curves,
each pair of the third 17 [airs of lines with the third pair of curves...
etc
and end up with 6 x 17 x 4 - {0,0} to {5,16} N=4 - points that I can draw closed polylines through to have 6 x 17 polylines - {0,0} to {5,16} N=1
Is this just not possible or am I just going about this the wrong way?
…
Added by martyn hogg at 2:57pm on December 18, 2014
a seed, and instead creating a pattern where each color has a seed/control slider for each row? For example, row 1: brown 2, tan 6, yellow 7, purple 3, repeat. row 2: brown 6, tan 1, yellow 4, purple 10, repeat. row 3: yellow 5, purple 1, brown 3, tan 10, repeat. row 4: purple 2, brown 7, tan 3, yellow 4, repeat. Then repeat that sequence up the wall? For each color, the number in the sequence should be adjustable.
Thank you again for your help!…
0, 5, 10, 15, 20
1, 6, 11, 16, 21
2, 7, 12, 17, 22
3, 8, 13, 18, 23
4, 9, 14, 19, 24
and if i'm here is because i'm not able... :)
can you help me?
thank you
…