ep is to understan the logics of what you want to do, in your case, build 4 point surfaces (u also need to know the right direction to build the surfaces). Then you can write an hipotetic list (by hand in a paper) of what you want. In your case the list was (0, 1, 3, 2) (2, 3, 5, 4) (4, 5, 7, 6), etc... if you can imagine building 2 lists, each one with the sequences (0, 2, 4, 6, etcc) and (1, 3, 5, 7, etc..) then you can manage with shift and graft to finally have four lists. A( 0 1 2 3 ...) B (1 3 5 etc..) C(3 5 7 etc..) D (2 4 6 etc..). And to achieve the 2 first lists, you need to get the odd and the pair numbers. The cull pattern does that amazingy well. With a pattern True-False you get de pair numbers, and with the False-True pattern you get de odd numbers.
Hope it was clear enough…
Added by Pep Tornabell at 5:32am on November 19, 2009
returned to GSA, it is solving. You might have to reset result scales using the GSA button.
Cheers,
Jon
Checking Input Data - this may take some time.
________________________________________
Data checks commenced at 23/08/2017 4:59:18 PM.
Checking input data for static analysis by GSS.
Shortest element (element 9) is 5 m long.Longest element (element 1) is 6 m long.
Data checks completed at 23/08/2017 4:59:18 PM. No errors or warnings found.
Analysis commenced at 23/08/2017 4:59:18 PM.
Analysis by Gss Static analysis
Initialising results modulesSolving for displacementsSolution statisticsSparse Parallel Direct 12 active nodes 14 active elements 2 analysis cases 24 degrees of freedom Minimum degree ordering 90 terms in stiffness matrix Maximum stiffness is 4.804e+009 at node 4 in direction z Minimum stiffness is 3.132e+008 at node 2 in direction yy Condition number of the stiffness matrix is ~ 5328. Maximum relative error in displacements will be 2.4e-10 percent. Factorization in 109 msSolving for element forces and reactionsCalculation completeAnalysis completed with no errors
Analysis completed at 23/08/2017 4:59:18 PM.Analysis time: 0.172 seconds
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now I want to combine some branches together ,the rule is : For path{2} contain number 2 and 5, then conbine the two paths together ,and for path{5} includes only 2&5,no other number ,so it's end .For path{3}, includes number 3&6 ,so we go to path{6}, path{6} includes 3&6&18, then wo go to path{18} , path{18} contains a new number 27, so we check path{27} ,path{27} includes only 27&18, no new numbers ,so it is end.
With this logic, path{2}&{5} become one tree finally , the contains is 2&5 ,and so path{3}&{6} &{18} &{27}(the contents is 3,6,18,27), and so others .
so what I want is:
{2}(2,5)+{5}(2,5)={2/5/anything}(2,5) ## the new path index doesnot matter{3}(3,6)+{6}(3,6,18)+{18}(18,27)+{27}(27,18)={3/6/18/27/?}(3,6,18,27) ``````etc
I tried path mapper, but I donot think it can do the trick this time. may be I just miss something very visible?? Awaiting for your kind help~Thanks in advance.…