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algorithmic modeling for Rhino

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Search Results - 山东体彩扑克3豹子-『1TBH·COM』北京pk10科学--2023年3月30日5时45分54秒.H5c2a3.thzj5jp9h-cc

Jiabao LiJiabao Li
Comment on: Topic 'matching 2 list's item'
IF 3 Towers obtain 1000, the 4th Tower doesn't exist. Hope that someone could help me in this!! …
Added by Landscape at 4:15pm on January 20, 2012
Comment on: Topic 'problem with flip function'
You need only 3 elements out of the 5 elements ? How do you decide which ones you want ?
Added by Yoann Mescam (Systemiq) at 1:49am on January 28, 2012
Comment on: Topic 'Variable List Merge / "Overwrite" Positioned List Values From Another List'
2 | 0 3 | 0 4 | 0 5 | 0   {0;1} 0 | A 1 | B 2 | C 3 | D 4 | E 5 | F   {0;1} 0 | 1 1 | 2 2 | 3 3 | 4 4 | 5 5 | 6   and so on...…
Added by David Lister at 7:37pm on June 5, 2011
Comment on: Topic 'Specific results(outputs) for specific inputs?'
    13             5    15             6    17             7    ...            … But it seems I have not been clear:   the input values (3,5,7,9,11,13) should be presented in the way of "number slider" parameter. So by increasing the value of the slider from minimum 3, to 5, 7, 9, 13, 15, 17... I should get an output numbers of 0,1,3,4,5,6,7...   So I if choose value 3 on the input "number slider", on the other end, I want 0 as an output. Or if I choose value 5 on the input "number slider", I want 1 as an output, and so on.   Is this possible?…
Added by djordje at 6:37pm on August 5, 2011
Comment on: Topic 'Tree Problems'
ave 63 branches in list B which shell be sorted by the indices from flattened list A. first indice is 3 so Branch 3 should be first in the new list, branch 45 second and so on, right?…
Added by JJK at 1:30am on September 20, 2017
Comment on: Topic 'Path Mysteriously Disappearing from Surface Closest Point to Evaluate Surface'
e) i.e. the points on the 5th curve of the 3rd surface where in branch {3;5}. Your surfaces tree was like {0;# of surface} i.e. your 3rd surface was in branch {0;3}. So you asked your Closest Point on Surface component to match your {3;5} points tree branch to your {0;3} surfaces tree branch... components are smart but not that smart. So you need to have a surfaces tree structure corresponding to your points tree structure, i.e. for each {3;x} branch of your points tree, you need a {3;x} branch in your surfaces tree with your 3rd surface in it. Hence the duplicate. I hope this clears it up a bit.…
Added by FRiou at 12:46am on July 20, 2015
Comment on: Topic 'Klein Bottle Equation Problem'
Cos(v)*Sin(u)-80*(Cos(u))^5*Cos(v)*Sin(u)+80*(Cos(u))^7*Cos(v)*Sin(u))…
Added by Daniel Christev at 7:30pm on January 20, 2016
Comment on: Topic 'Surface from points problem after delaunay mesh'
s points:)  …
Added by pbartek at 5:01pm on May 25, 2012
Comment on: Topic 'a "knot" problem'
identical knots on end ends of the curve, so the knot vector will look something like: 0,0,0,1,2,2,2 So one at each end and one in the middle. -- David Rutten david@mcneel.com Poprad, Slovakia…
Added by David Rutten at 3:47am on January 7, 2013
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