I extract the first two with a "Redim Preserve t(1)" command.
In the first case, the redim is correct, Line 7 = Line 2 and Line 8 = Line 3. It just kept the first two values like it is supposed to be.
But, for the second curve starting Line 9, some t values are messed up after the Redim. Line 16 = Line 17 despite Line 11 was different from Line 12. That's what is creating a problem later in the Split.
Weird.
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g generative aspect.
The three section approach was to give direct control over the number of points in the central section only. Its relatively easy to generate the rows of points
Oh! I was looking at it as a datatree exercise with path mapper.
I was trying to get:
1.{0;0;0} to {0;0;5} consistent N of 17 and
2. reversed {0;0;0} to {0;0;17} varying N
I havent quite solved that yet, thanks all the same.…
ilding owners and operators, fabricators, contractors and others who are interested in learning more about the latest facade technologies and design trends. I would like to try this now to read about the 5 ways ai will change the world.…
files are being imported as parameters still. I didn't replace all the image/json file addresses with my own files.
Then I have a second file (#19) where I replaced more of the line items with my own data but now the 3D images won't load. I have mostly dropbox links (per #17) but also one ftp link. I see this instead:
When I loaded my json file from dropbox or the ftp site into a plain webpage, it looked very similar to the dropbox json links from the DE example file. So I don't think it's the file itself. …
xed would be if it stretched. The force F is also being applied horizontally to the ends, which wouldn't make sense if they were completely fixed. The paper perhaps isn't very clear here, but I think they must be allowing the ends to slide horizontally.
Figures 18 and 19 map the distance s along the (curved) lath to the x axis and vertical deflection to the y axis ("Note that w is a function of s, which runs along the deformed shape of the lath"), and this shows that L is remaining constant (but not r).
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ay how many valid permutations exist.
But allow me to guesstimate a number for 20 components (no more, no less). Here are my starting assumptions:
Let's say the average input and output parameter count of any component is 2. So we have 20 components, each with 2 inputs and 2 outputs.
There are roughly 35 types of parameter, so the odds of connecting two parameters at random that have the same type are roughly 3%. However there are many conversions defined and often you want a parameter of type A to seed a parameter of type B. So let's say that 10% of random connections are in fact valid. (This assumption ignores the obvious fact that certain parameters (number, point, vector) are far more common than others, so the odds of connecting identical types are actually much higher than 3%)
Now even when data can be shared between two parameters, that doesn't mean that hooking them up will result in a valid operation (let's ignore for the time being that the far majority of combinations that are valid are also bullshit). So let's say that even when we manage to pick two parameters that can communicate, the odds of us ending up with a valid component combo are still only 1 in 2.
We will limit ourselves to only single connections between parameters. At no point will a single parameter seed more than one recipient and at no point will any parameter have more than one source. We do allow for parameters which do not share or receive data.
So let's start by creating the total number of permutations that are possible simply by positioning all 20 components from left to right. This is important because we're not allowed to make wires go from right to left. The left most component can be any one of 20. So we have 20 possible permutations for the first one. Then for each of those we have 19 options to fill the second-left-most slot. 20×19×18×17×...×3×2×1 = 20! ~2.5×1018.
We can now start drawing wires from the output of component #1 to the inputs of any of the other components. We can choose to share no outputs, output #1, output #2 or both with any of the downstream components (19 of them, with two inputs each). That's 2×(19×2) + (19×2)×(19×2-1) ~ 1500 possible connections we can make for the outputs of the first component. The second component is very similar, but it only has 18 possible targets and some of the inputs will already have been used. So now we have 2×(18×2-1) + (18×2-1)×(18×2-1) ~1300. If we very roughly (not to mention very incorrectly, but I'm too tired to do the math properly) extrapolate to the other 18 components where the number of possible connections decreases in a similar fashion thoughout, we end up with a total number of 1500×1300×1140×1007×891×789×697×...×83×51×24×1 which is roughly 6.5×1050. However note that only 10% of these wires connect compatible parameters and only 50% of those will connect compatible components. So the number of valid connections we can make is roughly 3×1049.
All we have to do now is multiply the total number of valid connection per permutation with the total number of possible permutations; 20! × 3×1049 which comes to 7×1067 or 72 unvigintillion as Wolfram|Alpha tells me.
Impressive as these numbers sound, remember that by far the most of these permutations result in utter nonsense. Nonsense that produces a result, but not a meaningful one.
EDIT: This computation is way off, see this response for an improved estimate.
--
David Rutten
david@mcneel.com
Poprad, Slovakia…
Added by David Rutten at 12:06pm on March 15, 2013
rotations per second. If I test the quad stepper on a smaller stepper like this one ((http://robotics.reefat.com/wp-content/uploads/2008/08/PF35T-48L4.pdf), I'm able to get faster speeds.
At first I thought this was a hardware/power supply issue, but I tested a sample sketch from this site: http://lusorobotica.com/index.php/topic,106.0.html on the Vexta NEMA 17 and was able to get the increased speeds I was looking for.
I can't get higher speeds than .3 rotations per second using the Quadstepper Component. Is there any way there a line in the code which is limiting the max speed?
Thanks for any help.
-Erick…
Added by lmnts to Firefly at 12:18pm on October 26, 2012
cept. Let's say you want to generate sun vectors for working hours. Let's say that people are working in an office from 8 to 17. It means they will leave at 5pm so the data for hour 5 shouldn't be generated. Does it make any sense to you! I tried to match Ladybug sunpath with daysim logic but I agree that it's not what comes to mind first when you hear 8 to 5.
Mostapha
PS: I like the time-saving component up there. How do you deal with the cutting hour?…