{4}-0;3
{5}-6;7
{6}-5;7
{7}-5;6
Here it can be shown that there are two subgraphs containing 0,1,2,3,4 and 5,6,7. How can I use spiderweb (either using scripting or the components) to give me this result when I have many more vertices??
Thanks,
Sam…
connect a graft component after second flattened list, decompose the points in XYZ, connect these 3 outputs + the grafted second list to a merge component with 4 inputs. You should end up with 5 branches of 4 elements each.…