So out of all these breps you want to union the ones that intersect each other in groups of exactly 4? If only 3 of them intersect, no union, if 5 or more intersect, no union?
Added by David Rutten at 9:07am on February 22, 2016
gh (3 times now).1. Install latest Rhino 5 beta 64-bit. Keep old Rhino 4 install.2. Copy over GH component files from Rhino 4 since you cannot specify the install directory when installing GH. Add GH as a plug in for Rhino 5.3. Install Karamba Free 0.9.083 to Rhino 4. I tried to install Karamba to Rhino 5 beta (under C:\Program Files\Rhinoceros 5.0 Beta (64-bit)\Plug-ins\Grasshopper\Components) but when I install no files appear in the directory.4. Copy all Karamba files to Rhino 5 directory.
5. Start Rhino 5 and GH. Karamba appears in the toolbar and everything appears fine, but I receive the below error from the Analysis component:
Error: Solution exception: The type initializer for 'fem.karambaPINVOKE' threw an exception.…
If you right click on the 'Random' component, you will find an option for "Integer Numbers".
You might need to generate random integers of 3, 4, 5 or 6 and multiply that by ten?
shift. I realize I can use 'replace branch' but I do not have an available mask to utilize. I have simplified the problem to its simplest form so my question is understandable, however, the tree I am trying perform this operation on is a much larger 3 digit path address.
{1;3;2}
{2;3;4}
{3;5;4}
{4;3;7}
Change the above list to the list below.
{0;3;2}
{1;3;4}
{2;5:4}
{3;3;7}
I wish for a more robust arsenal of branch manipulation components. Most of the things I need to do are possible with the existing components, however, many operations take several components to perform even simple manipulations. Since branch/path manipulation is so integral to using GH successfully, it seems the GH community would be well served by enhancing the available path manipulation components.
Thanks,
Stan
…
urs x 365 days ), and with modulus in the screenshot above, i could manage to do for every hour. but sometimes in my definition, i have a range from 1 to 35040, which is 365 x 24 x 4 ( 4 here defines every 15 minutes), on other word, when the number is one, then i have 01:00 O'Clock, when the number is 2 then i have 01:15 O'clock, when the number is 3 then i have 01:30 O'Clock...etc , so when the number is 97, which is the next day ( and after the number 96 which is equal 24 hours x 4), then I should have again 01:00 O'Clock.
I hope my idea is clear, thanks in advance!
Nassif…