Space Syntax

Comment

Comment by Pirouz Nourian on January 13, 2017 at 10:51am

Hi Asal, You are welcome. In the image you have posted I see that you have not provided any connections with the NEWS sides. Those links indicate your preferences for having access to one of these sides because of lighting or other reasons. Without these links it is not possible to make a triangulation. For making these links you need to draw additional lines towards the 4 sides to indicate adjacency. Note that in the end, you need to have enough links so that the graph is at least 3-connected. That means that the graph should not be torn apart by removing 3-1=2 vertices. For technical details see: http://mathworld.wolfram.com/k-ConnectedGraph.html

https://en.wikipedia.org/wiki/K-vertex-connected_graph

Please note that this is a theoretical limitation, not a bug. I hope this helps. 

Comment by asal alizade on January 13, 2017 at 8:37am

Hi pirouz

tnx for your quick response.

the error is:Object refrence not set to an instance of an object.

1.PNG

2.PNG

and I will read those chapters.tnx

Comment by Pirouz Nourian on January 13, 2017 at 7:41am

Hi Asal, 

Could you please post the content of the error message and an image of the network that is to be triangulated? It could be that there is no possible triangulation or that the number of triangulations is smaller than 9 (9=8-1). 

BTW, I'd suggest you look at the chapters 3 & 4 of my dissertation for an overview of the processes supported by the toolkit. http://abe.tudelft.nl/index.php/faculty-architecture/article/view/n...

Comment by asal alizade on January 13, 2017 at 7:25am

Hi Everyone!

I'm new in Space Syntax and now I have problem when trying to make the triangulation. I follow the example and also read the pdf but couldn't really find the solution.here is the screenshot:

ss.PNG

sss.PNG

anyone knows what is the problem?

thank u:)

Comment by h on January 2, 2017 at 1:31am

Yes, I know that but ForceDirectedGraph component only gives center of the circles within the graph. I wonder that it could give the areas of the circles in tangent position. I think I should calculate myself, as you told. Thanks. 

Comment by Pirouz Nourian on December 31, 2016 at 6:59am

@ h 

Hi, you can get the radii of circles by making an expression like Sqrt(A/pi), where pi equals 3.1415 and A is the area of the corresponding circle. this is because the area of each circle is pi*r^2 (pi times r squared)

Comment by h on December 30, 2016 at 4:31am

Hi, 

I am very new in GH. I want to use ForceDirectedGraph lines to set proximity relations with points. Because I want to use areas as constrains for point proximity in a plan organization. However, I cannot get those r values from graph. Thanks in advance.

relations.jpg

Comment by Pirouz Nourian on December 19, 2016 at 3:15am

Hi Yalda, please make sure the units of the Rhino file and the radii values are the same (e.g. meters). If you aim for large radii when the boundary is small you'll get errors because the boundary cannot fit circles that big. Please start from the example file. If something went wrong again, please attach your file to a comment here and I'll look at it. 

Comment by Yalda Sharifi on December 18, 2016 at 12:09am

Thanks for explanation but I didnt have any result because of an error on radii data.As Im beginner user, I still dont know is there the logical relation between radii and boundry curve or just a restrictive...

Comment by Pirouz Nourian on December 15, 2016 at 1:14am

Hi Yalda, you can use it like the grasshopper's Voronoi diagram component with a list of points and a boundary curve plus a list of areas to be used as the weights. You can check the demo file for an example. The demo file comes in the installed folder.

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