Grasshopper

generative modeling for Rhino

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Constrained Perimeter3 Replies

Hi,I have been trying to create a rectangle that had a constrained perimeter (ie. say 4) when i change the x and y dimensions in order to get a variety of shapes/scales.For exampleOriginal…Continue

Tags: perimeter

Started this discussion. Last reply by fb Jul 15, 2010.

surface morph2 Replies

Hi!I am wanting to morph a geometry onto a surface which is divided into sub surfaces (which arent based on uv division), but i cant find a way to do it!I am aware of the surface box and morph way,…Continue

Tags: surface, morph

Started this discussion. Last reply by fb Nov 3, 2009.

Finding the intersection points between curves

Hi!Can anyone help me out?I am trying to find the intersections between a series of lines in the x direction and another series of lines in the y direction and use these points to define a series of…Continue

Tags: curve, intersect

Started Oct 27, 2009

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Uni Melb

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At 12:59pm on November 8, 2009, Matteo Lo Prete said…
Hi Morgan,
the receiver is connected with another piece of my definizion which defines how the component's arches open. It is a parameter, for me.
You can see this part here:

Well, the first receiver (top left) is connected with the list which contains the centroids of every triangle of my mesh (my canopy, that I turned into a series of triangular surfaces). In this part of the definition I evaluate the Z coordinates (extracted form the points).
I execute some operations in order to have my values from 0 to 1 (parametrization). Then I sutracted the lower value of the list to all the data. So I obtained a new list of numbers, which stay from 0 to 1 and I can use in order to determine a gradient in the arch openings.
The result? If you look carefully to the rendering I posted you'll see that the arches are less opened near the ground and more opened near the top. It's a structural way of design the canopy. The more loads you must support, the more closed your arches will be (and the more stronger you should be).

Anyway consider this part as not important, because this parameter is just a my interpretation, it's not essential in order to obtain the canopy I posted. If you want you can just substitute that emitter with a simple number, from 0 to 1. Don't know, try to put 0.4 as an imput and let's see what happens. The result will be more similar. ;-)

Nice to meet you Morgan.

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