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generative modeling for Rhino

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Constrained Perimeter
3 Replies

Hi,I have been trying to create a rectangle that had a constrained perimeter (ie. say 4) when i change the x and y dimensions in order to get a variety of shapes/scales.For exampleOriginal…Continue

Tags: perimeter

Started this discussion. Last reply by fb Jul 15, 2010.

surface morph
2 Replies

Hi!I am wanting to morph a geometry onto a surface which is divided into sub surfaces (which arent based on uv division), but i cant find a way to do it!I am aware of the surface box and morph way,…Continue

Tags: surface, morph

Started this discussion. Last reply by fb Nov 3, 2009.

Finding the intersection points between curves

Hi!Can anyone help me out?I am trying to find the intersections between a series of lines in the x direction and another series of lines in the y direction and use these points to define a series of…Continue

Tags: curve, intersect

Started Oct 28, 2009

 

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fb replied to fb's discussion 'Constrained Perimeter'
Why thanks Paolo, greatly appreciated ;) i had been fiddling around with it for a couple of hours!
Jul 15, 2010
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Paolo Cappelletto replied to fb's discussion 'Constrained Perimeter'
...Created in GH 070030
Jul 15, 2010
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Paolo Cappelletto replied to fb's discussion 'Constrained Perimeter'
I hope it will be helpful. Paolo
Jul 15, 2010
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Constrained Perimeter

Hi,I have been trying to create a rectangle that had a constrained perimeter (ie. say 4) when i change the x and y dimensions in order to get a variety of shapes/scales.For exampleOriginal rectangle perimeter = 4x = 1y = 1New rectangleperimeter = 4x = 1.5y = 0.5etcDoes anyone know how to?See More
Discussion posted by fb Jul 15, 2010
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fb commented on Matteo Lo Prete's photo
thats a really interesting pattern! congrats what is the basic components/techniques you used?
Nov 5, 2009
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fb replied to fb's discussion 'surface morph'
thanks ill give that a try!
Nov 3, 2009
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Vicente Soler replied to fb's discussion 'surface morph'
You can still create twisted boxes by extracting the 4 corners of each surface for the bottom corners of the box. For the top 4 corners just move them using the surfaces normal at each point.
Nov 1, 2009
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fb replied to JAK's discussion 'uneven pt grid to subsurface'
hi just wondering if you found that out? i would like to know if you have because i am trying to do something similar
Nov 1, 2009
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surface morph

Hi!I am wanting to morph a geometry onto a surface which is divided into sub surfaces (which arent based on uv division), but i cant find a way to do it!I am aware of the surface box and morph way, but seeing that the surface is divided into squares rotated 45deg its a slightly different storyDoes anyone know a way?See More
Discussion posted by fb Nov 1, 2009
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Finding the intersection points between curves

Hi!Can anyone help me out?I am trying to find the intersections between a series of lines in the x direction and another series of lines in the y direction and use these points to define a series of surfaces.I just cant find the right component!ThanksSee More
Discussion posted by fb Oct 28, 2009
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fb updated their profile Oct 28, 2009
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fb is now a member of Grasshopper Oct 22, 2009

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At 12:59pm on November 8, 2009, Matteo Lo PreteMatteo Lo Prete said…
Hi Morgan,
the receiver is connected with another piece of my definizion which defines how the component's arches open. It is a parameter, for me.
You can see this part here:


Well, the first receiver (top left) is connected with the list which contains the centroids of every triangle of my mesh (my canopy, that I turned into a series of triangular surfaces). In this part of the definition I evaluate the Z coordinates (extracted form the points).
I execute some operations in order to have my values from 0 to 1 (parametrization). Then I sutracted the lower value of the list to all the data. So I obtained a new list of numbers, which stay from 0 to 1 and I can use in order to determine a gradient in the arch openings.
The result? If you look carefully to the rendering I posted you'll see that the arches are less opened near the ground and more opened near the top. It's a structural way of design the canopy. The more loads you must support, the more closed your arches will be (and the more stronger you should be).

Anyway consider this part as not important, because this parameter is just a my interpretation, it's not essential in order to obtain the canopy I posted. If you want you can just substitute that emitter with a simple number, from 0 to 1. Don't know, try to put 0.4 as an imput and let's see what happens. The result will be more similar. ;-)

Nice to meet you Morgan.
 
 
 

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