algorithmic modeling for Rhino
A = {0;1;0}
B = {0;1;0;1}
C = {0;1;0;0;1;0;0;0}
After simplify ,I get:
A = {1}
B = {1;0;1}
C = {1;0;0;1}
And if the tree structure is something like:
A={0;0;1;0}
B={0;0;1;1}
C={0;0;1;2}
After simplify ,I get:
A={1;0}
B={1;1}
C={1;2}
But If the tree is:
A={0;0;0;0;0;0}
B={0;0;1;0;1;0}
C={0;0;1;0;2;0}
I get:
A={0;0}
B={1;1}
C={1;2}
WIsh #3
I came across conditions that there is no direct way to handle some Datatree matching problems . And now I think I find what's the problem :GH now lack the capability to make cross reference between lists/branches .For example, I have two trees ,the first one have two branches {0}&{1}, the other have three branches{0}&{1}&{2}.Now GH would do:
what I want is :
After that, Maybe we could match [{0};{1}] and [{0};{1};{2}] very easily (Longest List;Shortest List;Cross Reference) ??
I tried to explain the concept of "tree" to my friends ,but I am confuzed somewhere myself .For example ,how could we have a tree including branches {0},{0;0}and{0;0;0} at the same time??{0} should be the biggest tree trunk,and {0;0} is part of {0} .{0;0;0} is just the smallest trunk and store the least data inside .How could the biggert trucks are empty while only the smallest branches contain items ?(David drawed a datatree that tell this,remember??)
But if this idea is acceptable ,then I could make a fairy tale about tree to them :
(Long long ago...)
[0] is a tree ,[1] is a tree.
{0},{1},{0;0}.{0;1;0} are branches.
{0}=(0,1,2,3,4,5) is branch.
[0]= [{0;0;0};{0;0;1};{0;0;2] is a standard tree .
[0]=[{0;0;0};{0;0;2};{0;0;3] is a pruned tree.
[{0};{0;0};{0;0;0}] is an illegal tree .
Gh is lenient enough to allow the existence of illegal tree .
Gh is lenient enough to allow the existence of empty trees& empty branch&null items.
We can use PathMapper to transform an illegal tree into a legal one and vice versa .Wish #4
wish for Split List component : it would have a wrap option just like many other components.In this way , we can split a list of data at -1 .I think this would be useful .
wish #5
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