gone with the wind topic: since this is utterly Academic the main issue here is to oversimplify LBS (in real life: a collection of columns/beams/slabs/X members + tube frame rigid members (shafts/elevators/cats/dogs)). Reason is that if we use the real "solids" (turned into meshes) as the "node" pool for the hinges required ... only HAL 9000 could solve it in "real-time" (for instance an E5 Xeon 1630 v3 takes ... several minutes). And this is ... er ... challenging I must say. This is a typical case where "simplifying" means "stupidity" almost instantly.
Spam on:
where's my collection of "bend-a-truss-that-looks-like-a-tower" K1 demo defs? Is in this workstation or in another? (blame Alzheimer).
Spam off.
More soon.…
thankssssss
.74-.80 may is ok not big differents .. but i have to control each group of triangles :)
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sorry the version is
rhino 4.9
gr 0.8.0004 version
thanks :)
Added by architecture at 6:26am on December 20, 2011
ven if the number of panels inside each cell varies. The current solution works when the number of panels inside each cell is always two or other same numbers, but it wouldn't work if the number of panels inside frames are different in each cell. It would be perfect, if numbering of panels are automatically added correctly next to the cell number based on the number of panel division instead of feeding the fixed number.
To take an example, let's assume that the cell #80 has three panels and the #81 has two ones. In this case, three panels within the cell #80 would be numbered like 80-1, 80-2, 80-3, while two panels within the #81 would be numbered such as 81-1 and 81-2 automatically. …
ded a circle and been able to draw the two lines and cull out the correct distances but do not know how to pull out those two original lines - the one from the starting point to the circle division + the circle division to the end point.
To recap - I'm looking for a way to have 2 lines = 80" when the direct path between two points is 60". I do not want the 2 new lines to be equal in length but variable lengths.
thanks!
_patrick
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tries, of different types, both annotation objects and curves, won't it be slow to iterate through all these objects for each rectangle?
I use 0.6.X but i'm soon making the shift to 0.7.X…
ve is most impacted by the characteristics of the vector field...If accuracy is not so important, you can use the curve re-sampling components to create a smoothe curve.…
dro). The quality of the driver is also critical: hard to imagine NVidia working overnight to fix "some" driver bugs due to requests from gamers. Game cards are notoriously bad in dual monitor configurations.
3. A zillion of cores (triumph of marketing VS common sense) divided by the given clock rate ... gives you just ONE poor old core (Rhino/gh are single-threaded apps) that tries to do the job.
4. Single Xeon E5 2xxx V3 (the higher the clock the LESS the cores = better) would be my recommendation. ECC fast memory is also a must.
PS: Find a friend who operates a "loaded" H/P Z840 and test your defs.
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of lines, etc) but I can't see a way to add the text I need where I need it. If I could get each line for the print run to generate automatically, I can put the rest in manually, so just need something like:
... ; I would do the previous to this manuallyG1 X10 Y5 Z3
G1 X5 Y5 E5
G1 X5 Y15 E10
... ; I would do the rest manually
for a 5 mm line from [10, 5, 3] to [5, 5, 3], followed by a 10mm line from there to [5, 15, 3]. Any pointers greatly appreciated.
Ewan…