inal surface, creating buckling.
http://www.grasshopper3d.com/forum/topics/differential-growth-in-curves?id=2985220%3ATopic%3A1313465&page=1#comments
I experimented with many different texture effects. In the end I decided i liked the idea of the outer surface being eroded smooth. With the articulate texture protected within folds.
Full GH (Kangaroo - Meshmachine - Weaverbird - Millipede)…
Added by Nick Tyrer at 5:25am on December 10, 2015
ase to give the same result using a graph mapper with a parabola as in the attached file
Unfortunately it never gave the same result ..... is it a mistake in the book ?!…
1. Buy some anti gravity tissue (available on request by Fotiadis ACME Industries: any color you want, payment in advance, cash only).
2. Create a pavement with a rectangular hole. Use Buchtal Bosco tiles (the most expensive stuff around > we live once). Avoid trees (it's too late) and/or anything (Less is more).
http://www.agrob-buchtal.de/en/cd/produkte/produkte_seiten_2_19881.html?pe_id=88
3 .Put Vodka into the hole (I do hope Russian top stuff).
4. Do a semi submerged grid of tissues (vertical due to 1 - or your money back).
4. Provide armchairs to the spectators (these things take time). Put ZZTop on the stereo (or Cure). Empty your mind. Reset.
5. Wait for some appropriate wind and/or the 4 horsemen (whatever comes first).
Moral: ResetNowForEver…
rees west to 1 degree west). Changing the latitudinal domain from, say, 0:1 (the equator to 1 degree north) to 88:89 (88 degrees north to 89 degrees north), has zero effect on the x,y shape of the topography map generated. However, in reality, the map should be far, far thinner in the latter case, because longitudinal lines get closer together toward the north and south poles. In actuality, the shape should be close to a trapezoid in both cases, but this is probably not a necessary detail for most people producing maps, since, at an urban or smaller scale, the latitudinal lines bounding the north and south of the map will probably not be that significantly different in length. But the maps should at least stretch from close-to-square for a 1 degree x 1 degree map near the equator to an extremely thin rectangle for a 1 degree x 1 degree map near the north pole.
As an example, I'm looking at a location in Sheffield, UK. The relevant SRTM HGT file spans from 53 N to 54 N, and 2 W to 1 W. The length of the map in the north-south direction should be approximately 111 km, as is the case with the topo map generated by Elk (and a near-standard for 1 degree latitude anywhere in the world). The length of the map in the east-west direction, however, should be somewhere in the range of 67 km, since the 2 W and 1 W longitudinal lines are much closer together at this latitude than they are at the equator. Thus the map should be nearly twice as long in the North-South direction as it is wide in the East-West direction.
If this were to be sorted out, I think it would be really nice to then have the SRTM topo map be positioned automatically in relation to the OSM map being brought in. I think it's good that the OSM map is positioned at 0,0, rather than it's world coordinates, but maybe the SRTM topo map could be aligned with it based on the latitude and longitude domains we input to the SRTM grasshopper module.…
moved by random amounts in a random direction. The animated slider was the amount of deviation from the original points. And yes, I used culled lists.B.t.w. did you find my workaround for your loft? Did your notebook explode? ;)…
but as one would imagine after 6 or so 'animals' it gets so large that the machine starts to crawl :/
88% of the resources come from the permutation script, my guess is that if the permutation were calculated on the fly with the counter(the engine) it wont have to pre-compile the list which would be much faster...
If anyone has an idea im all ears....
I attached the file (re-written in C#) …
make a new curve from points I attempt to do it by writing:
Curve cv = new Curve();
This gives me the error:Error: 'Rhino.Geometry.Curve.Curve()' is inaccessible due to its protection level (line 88)
I have also tried calling the CreateInterpolatedCurve() from the Curve class, but
Curve cv = null; cv = new Curve.CreateInterpolatedCurve(Mould.Branch(0), 3);
But from this i get:
Error: 'Rhino.Geometry.Curve.CreateInterpolatedCurve(System.Collections.Generic.IEnumerable<Rhino.Geometry.Point3d>, int)' is a 'method' but is used like a 'type' (line 89)I'm really quite lost about how I can this to work. Can anyone help me?…