ed according to list C.
I tried replace members, but it consists of geometry, so it doesn't worked.
In list C I filtered all the indices that need to be replaced.
All items in {0;0} from C need to be replaced by List B {0;0}
All items in {0;1} from C need to be replaced by List B {0;1}
And so on...
In the end everything needs to be fed into a orient component.
G is the geometry behind list B
A is the new list (but I don't know how to create)
B is the list A of all 60 panels
To wrap up the question:
I need to have entry 1 from list B in a new list on position: 0 1 2 3 5 6 7 10 11 12 15 16 21
I need to have entry 2 from list B in the same new list on position: 4 8 9 13 14 etc. etc. etc.
I wonder how I can do this :) Thanks in advance!
…
he implementation of the Component more autonomous without the need for user intervention.
At present you have 1 main input for the data to be placed on a single sheet as per the input and the option to add more sheets manually.
Would it be possible to alter this to have a Data input and a Sheet Name Input so that the Path Structure dictates which sheet gets what data and the optional Name input gets applied.
For example
{0;0;0}(N=10) is Range A1:A10 on Sheet 1
...
{0;0;9}(N=10) is Range J1:J10 on Sheet 1
{1;0;0}(N=10) is Range A1:A10 on Sheet 2
...
{1;0;9}(N=10) is Range J1:J10 on Sheet 2
etc.
I realise that this would have to be very particular, making sure that only Place Holder A has influence over what sheet is used If there is a distinction of multiple sheet names.
For Example if you had a list of:
{0}(N=10)
{1}(N=10)
{2}(N=10)
{3}(N=10)
Place holder A could either be sheets or Rows so it would have to only work when there was a corresponding Sheet Names List for {0}, {1}, {2} and {3}
At present I have to do this manually using Explode Tree etc. Whenever I expand on the conditions (different Draft or Heel) Then I have to increase all of the outputs for the components highlighted in Pink
…
Hi Mostapha,
I'm getting the same error as Apoorv Goyal on August 31, 2015 at 4:53pm. How can I fix it? I wasn't able to understand your recommendation to him.
to 10 = color 2
10 to 15 = color 3
15 to 30 = color 4
....
I divide the surface by number of segments. How can I divide the surface by distance between
any help...…
e perimeter of each floor into 32 points (as you can see in the draws). I want to connect each point like a dual direction net. I think that i have to use some math parameter to filter the points of the list that i want to join, but i just can't find the way. In theory i know that i have to join the 0 point of the first curve to the 1 of the second, and then to the 3, and son on ... and after this the opposite (the 0 to the 32, to the 31). Anyone has an idea? …
older was not recognized:
But now the panel displays this COM class factory error
I have followed all the instructions at point 1 without results.Someone else has had the same problem? How can I solve?
Regards,
F.
…
ed to loft between in a consecutive manner ie. between the 1st and 2nd line, between the 2nd and 3rd line, between the 3rd and 4th line etc.
Thus I believe if I can manipulate the list of 10 planar curves into something that looks like the following, I could plug that list into a loft component to create 10 develop-able strips for my pipe!0 | Planar Curve1 | Planar Curve______________1 | Planar Curve2 | Planar Curve______________2 | Planar Curve3 | Planar Curve..._____________8 | Planar Curve9 | Planar CurveBelow are some screen grabs of what I've done so far, if there are better ways to go about this I'm also interested in that.
Cheers, ScottN.B. I know this script functions perfectly fine, I'd just like a script that is not as heavy and can be applied to larger, more complex geometries.
…
om.
I've attracted a sample file. Those curves are not planar. Please let me know if more info is needed.
Rhino file DL link:
https://s3-us-west-1.amazonaws.com/gorhinoceros/Test.zip
Thanks!
…