ide into 80 branches, and 80 outputs of explode and 80 dispatches - its my nightmare. Is there any way to do this with parametric Number of brunches? …
, a1200)}) Is there any way I can make this list into {a1, a2, a3, a4, -a5, -a6, -a7, -a8, a9, a10, a11, a12, -a13, ..... , a1200} ? ( 4 positive signs then 4 negative signs and so on) - alternating every nth in general.
or
2. Is there any way (workaround) to get negative angle value from 2 vectors? I know 'ANGLE (of 2 vectors)' component by itself doesn't work and I know why too. I have feeling that the reflex angle output might be useful but again, matter of list manipulation.
Any help would be greatly appreciated. Thanks in advance.
Hyo
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rom two surface offsets. I did a merge list to create a pattern from an wavy surface. I obtained several surfaces made of two toggle boolean.
Capture%20d%E2%80%99e%CC%81cran%202016-05-18%20a%CC%80%2016.26.16.png
How can i simplify those surfaces (made of two surfaces)?
Capture%20d%E2%80%99e%CC%81cran%202016-05-18%20a%CC%80%2016.26.38.png
Also, how can i link the two offset surfaces in a closed volume?
Thank you guys!
Best,
Rémy…
dro). The quality of the driver is also critical: hard to imagine NVidia working overnight to fix "some" driver bugs due to requests from gamers. Game cards are notoriously bad in dual monitor configurations.
3. A zillion of cores (triumph of marketing VS common sense) divided by the given clock rate ... gives you just ONE poor old core (Rhino/gh are single-threaded apps) that tries to do the job.
4. Single Xeon E5 2xxx V3 (the higher the clock the LESS the cores = better) would be my recommendation. ECC fast memory is also a must.
PS: Find a friend who operates a "loaded" H/P Z840 and test your defs.
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of lines, etc) but I can't see a way to add the text I need where I need it. If I could get each line for the print run to generate automatically, I can put the rest in manually, so just need something like:
... ; I would do the previous to this manuallyG1 X10 Y5 Z3
G1 X5 Y5 E5
G1 X5 Y15 E10
... ; I would do the rest manually
for a 5 mm line from [10, 5, 3] to [5, 5, 3], followed by a 10mm line from there to [5, 15, 3]. Any pointers greatly appreciated.
Ewan…
nt B2[i] so B1[i]<=0 means no new connections allowed for point i ,so point i is deleted from B1, B2 updated accordingly.
Initialization:
B1: max number of connections x number of points
B2: all the points
B3: nothing (well null or something, need to create the branch)
Algo:
Get first point in B2, get his allowed number of connections N in B1, find N closest points in B2, create lines in B3, update B2 accordingly. Erase points with max connections (including the first point)
Next
Stop when no points available
At end of loop, B3 stores the created lines.
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