ee 3)
{5}
0 15
{6}
0 16
And I want to place points at every possible combination of these coordinates, treating Tree 1 as X coordinates, Tree 2 as Y coordinates, and Tree 3 as Z coordinates. Also, I would like the list of points to be a tree with paths corresponding to the coordinates. Wouldn't it be nice if I could plug these trees into a Point XYZ, with a new "branch cross reference" method, and get the following result?
{0:3:5}
0 {10.0, 13.0, 15.0}
{0:3:6}
0 {10.0, 13.0, 16.0}
{0:4:5}
0 {10.0, 14.0, 15.0}
{0:4:6}
0 {10.0, 14.0, 16.0}
{1:3:5}
0 {11.0, 13.0, 15.0}
{1:3:6}
0 {11.0, 13.0, 16.0}
{1:4:5}
0 {11.0, 14.0, 15.0}
{1:4:6}
0 {11.0, 14.0, 16.0}
{2:3:5}
0 {12.0, 13.0, 15.0}
{2:3:6}
0 {12.0, 13.0, 16.0}
{2:4:5}
0 {12.0, 14.0, 15.0}
{2:4:6}
0 {12.0, 14.0, 16.0}
In this form of cross referencing, every combination of individual branches from the different lists is used as separate input, and the output for each combination is put onto a branch in the result whose path is the concatenation of the input branch paths used.…
Added by Andy Edwards at 7:03pm on November 3, 2009
Thank you,
I had indeed the offset issue with this component but solved (from another discussion) rebuilding original curve with 24 control point instead of 3
Each corner of mesh A has got a partner on mesh B.
I don't get it. One mesh has 24 points, the other 26. How can they be paired up?
--
David Rutten
david@mcneel.com
Added by David Rutten at 5:51am on December 27, 2013
quel que este interesado en aprender procesos Generativos y Paramétricos con Grasshopper para Rhino 5.
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…
the first area and the first number, the second area and the second number and the third are and the third number. For example, let's assume we have the following areas {65, 15, 20}. The absolute difference between these two sets equals {abs(44-65), abs(39-15), abs(17-20)} == {21, 24, 3}. The sum-total of all these absolute differences is your fitness, i.e. 21+24+3 = 48. This number has to go to zero.
If we enter the results you just got, then the absolute differences look like this: {abs(44-44), abs(39-17), abs(17-39)} == {0, 22, 22}, which results in a fitness of 44. Only an exact match will result in a fitness of zero.
--
David Rutten
david@mcneel.com
Seattle, WA…
Added by David Rutten at 12:44pm on November 13, 2010