would like to group the paths based on their item count (n) values resulting in a tree which should look something like this:
{0;0} (3)
{0;1} (2)
{0;2} (2)
{0;3} (1)
in other words, all paths with 2 items are under one path, all with 6 items in another, and so on.
I feel that the pathmapper should be able to do this very easily but cannot figure out what the expression should be... I have tried searching the forum but have not had much luck!
Any ideas? Thanks a ton!…
ggle A
7. Toggle A
8. Toggle 2
9. Toggle 3
10. Toggle A
11. Toggle A
12. Toggle 3
I was thinking to use somehow slider and animate option....but without luck
Any idea would be appreciated…
ersect (2, 3, 4, 5, 6) with the line and the ones which do not intersect (0, 1, 7). Intersect is done! But how to get the non intersecting vectors (0, 1, 7)?
So I e. g. could deselect vectors 2, 3, 4, 5, 6 so I would display/use only vectors 0, 1, 7 and the bounced ones.
Appreciate your help!
Rudi…
created surface with sweep and rotate them with number of division. Section curves of 2Railsweep is defined with 3 Point arc and shape is also controlable.
You can change shape by sliding 16 paramteters.
The definition is rather long, hope somebody can modify with more sphiscated manner.
日本語
パラメトリックにボトルデザインをする.ghxファイルを作成しました。ボトルのプロファイルカーブを、参照となる円に対して、高さ、シフト、オフセットでコントロールポイントの位置情報を与えて定義。次にスイープで分割数だけ回転コピーして作成。
スイープの断面、3点円弧で作成し、形状コントロールするようにしています。
ボトル形状は、16のパラメーターをスライドすることで定義出来ます。
…
a follow up question... how do I wrap a list onto itself at a certain frequency?
i.e. I want the list {1;2;3;4;5;6;7;8;9}
to become {1,4,7; 2,6,8; 3,6,9} wrapped every 3rd item
Added by Joshua Jordan at 5:30pm on November 17, 2012