} (N=11) {0;1} (N=11) {0;2}(N = 11) {0;3}(N = 11) {0;4}(N = 11)
2. I run the Points that are coming out from the Divide Curve Components through the Path Mapper components with this definition:
{A;B} (i) > {A} (i)
3. I run data coming out from Path Mapper component through:
a) Parameter Viewer component and the result is:
{0} N=11 (data with 1 branches)
b) Point > Panel and the result is:
collection of 11 point (N=11) which is the exactly the same as the collection of point belonging to {0;4} (N = 11).
So, here is the question:
why the collection of points coming out from the Path Mapper {A;B} (i) > {A} (i) component is the same as the collection of points belonging to the curve {0;4}(N = 11) ?
Anyway ... It 's the first time I ask a question here... so I would like to thank you for what you do with your work! Thank you! You are really great!…
this, you'll have no horizontal force at the roller, but you will have it at the pinned support. If you wouldn't, then the structure will be displaced.
Usually, in 2 dimensional structures, if you want to know if an articulated structure is isostatic (as opposed to hyperstatic, which is what you have right now) is to use the following formula:
b+c-2·n=0;
b being the number of bars, c the number of constraints you have and n the number of nodes. In your case: b=19, c=3 (displacements constrained in X, Z at your pinned support and only constrained in Z at your roller support) and n=11, so: 19+3-2·11=0.
I recommend you to download the app SW Truss, as it's very useful to check your results instantly.…
vector * number
8. number * point
9. point * number
10. complex * complex
11. colour * colour
12. colour * number
13. number * colour
--
David Rutten
david@mcneel.com
Seattle, WA…
Added by David Rutten at 10:39pm on November 12, 2010
a specific domain, for example:
0.) 0 to 1 -----> 11 random values from 0 to 1 (0.245,0.678,0.36,0.78,.28,0.18........)
1.) 1 to 2 -----> 11 random values from 1 to 2 (1.26,1.36,1.01,1.68,1.26,1.96.........)
3.) 2 to 3 -----> 11 random values from 2 to 3 (2.96,2.45,2.78,2.56,2.98,2.10..........)
4.) 3 to 4 and so on where I have a data set containing 11 paths with 11 values and the values fall within the specific domain.
Like my post above I have the correct path but I need to feed it the correct seed to get different values for each number. I tried grafting a series similar to the last post but it scrambles my data. Thanks so much for the help!
…
Pérez Albà McNeel Europe presents Rhino 5.0, Matus Nedecký (flying architecture) and Fabio Palvelli (3D Dreaming) show VRAY for Rhino and rendering services for architecture. We also show the new Wacom Cintiq 22 HD touch.
There are 2 events, the first at 15:00 and the second at 18:30. Places are limited to 30 people each.
As a special event you can switch between the events at a basic coffee seminar "Coffee - from the plant to the cup" part. Coffee Museum in Austrian society and economy museum was founded by Edmund Mayr, who injected together with Arch Wilhelm Holzbauer, the increase of the flak tower in Esterhazy Park. His passion for collecting are also due to the many exhibits that he has collected from all over the world. Additionally Mag. Just shows a quick roundup of "100 Years of Life and Living in Vienna" and how the inventions of Dr. Carl Auer von Welsbach changed the world significantly.
program: 15:00 to 15:45 Presentation software Autodesk Maya 2014 (group 1)
15:45 -. 16:00 Tour "100 years of life and living in Vienna / Dr Carl Auer von Welsbach in the Agricultural Museum (Group 1)
16:00 to 16:45 Presentation software Rhino 5.0 and VRAY (group 1)
5:00 p.m. to 6:15 p.m. basic coffee seminar "Coffee - from the plant to the cup" with Mr Edmund Mayr
18:30 to 19:15 Presentation software Autodesk Maya 2014 (Group 2)
19:15 -. 19:30 Tour "100 years of life and living in Vienna / Dr Carl Auer von Welsbach in the Agricultural Museum (Group 1)
19:30 to 20:15 Presentation software Rhino 5.0 and VRAY (Group 2)
20:15 finger found, drinks and "Come Together"
22:00 End of the event
Participation is FREE, due to the limited number of places but registration is required. To register for the event, we ask you to select the following options:
Online Registration 15:00 http://www.kkkc.at/component/seminar/?task=3&cid=5
Online Registration 18:30 http://www.kkkc.at/component/seminar/?task=3&cid=6
or by email: office@kkkc.at
or Tel: 01-545 78 25…
1:
{0} N=5
{1} N=6
and a tree 2:
{0;0} N=1
{0;1} N=1
...
{0;18} N=1
{1;0} N=1
{1;1} N=1
...
{1;19} N=1
I want to basically modify Tree 1 in order to get
{0;0} N=5
{0;1} N=5
...
{0;18} N=5
{1;0} N=6
{1;1} N=6
...
{1;19} N=6
which is the Tree 1 with the structure of Tree 2 and the items of Tree 1 {0} branch populated at each {0;*} branch of Tree 2 and the items of Tree 1 {1} branch populated at each {1;*} branch of Tree 2.
…
i mean, i want a slider that can do 3 sides, 4 sides, 5, 6, 7, 8, 9 and 10. for the grids because I dont want to use a fixed grid shape such as square grid (4 sides only).