ll to one end of the field.
Here's another, slightly more involved way to approach it:
1. create an even, random field of points
2. sort them in the direction of the gradient (decompose the points into xyz and sort by z value, for instance)
3. plug the sorted points into the jitter component and use a slider to control the amount of jitter
4. use "split list" to extract one half of the list (use list length/2 as the index)
5. adjust the jitter amount - at 0 you'll get a solid block of the top half of the random points, at 1 you'll get a random set of 50% of the points, but somewhere in between you'll get the appearance of a gradient.
Let me know if any of this is unclear... hope this gets you started.
Andrew…
make the surface, it is twisted. i think this is happening because as the points are computed, the surface morphs. as an alternative, i'd like to make 5 curves and loft those curves. the first 7 points = 1st curve, next 7 = 2nd curve, etc.
does anyone have a suggestion how to do this?
thank you.…
lso, I have another data tree (panel_2) holding x,y,z values for only 8 geometries on the screen. I wanted to select only 8 branches from data tree 1 (panel_1) according to x,y,z values holding in the second tree (panel_2). Is it possible to do that?
many thanks in advance.…
maths. I have done a definition with transform hexagon of Width 2 and height Sqrt(3) to diamond of width 3 and height 3Sqrt(3). But I am not sure that it is what they did.
The transformation is like this
1) a scale factor depending on Z, 1 it is hexagon and 3 a diamond, this scale is represented by the graphmapper
2) This scale is integrated on Z and it generated a new Z scaled
3) each hexagon point is transformed on X depending on the scale factor (linear transformation between an hexagon to a diamond), the transformation on Z is just an interpolation on Z scaled.
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