) function if you've already got a boolean value.
This expression:
x < 12
results in exactly the same things as this expression:
If( x < 12, True, False )
If() is only really useful when you want to return non-boolean data, like so:
If( x < 12, x, 100-x )
In this case, the expression will return either x, or 100-x if x is larger than or equal to 12:
x result
1 1
2 2
10 10
11 11
12 88
13 87
14 86
18 82
70 30
--
David Rutten
david@mcneel.com
Poprad, Slovakia…
Added by David Rutten at 7:22am on August 10, 2011
e range of materials, including heavy-duty fabrics. They offer a range of embroidery machines that cater to different needs and budgets.best embroidery machine for custom designs…
to make a lot of problems when you divide second set of curves because everything is counted double times.
the target is to find the right way to list items directly linked with u/v divisions.
check the number of items you have after dividing the srf.
by the way thank you for your interest.…
7 -18.2
8 5.02
9 12.4
10 18.1
11 7.01
12 5.11
13 2.35
this data is waveform data.
i want to pick out only climax(for example in upper data, number 1 and 10) from this data.
i have this problem...that is, i do not know to do what.
i think my English is strange...so you are difficult to understanding my question.…
nique name like in your example {0;0},{0;1},{0;2},{0;3} where each path contains 11 elements(curves,points,values,etc)
so if you want to restructure the structure first right click on path mapper and take create null mapping which reads your current path structure into the component
after that you can additional write on the left side to the existing path (i) as variable for the elements and then on the right side type in the structure you want to achieve
maybe {A;i}(B) so after that you have 11 paths where each have 3 elements
hope that helps…
GH. The grey plastic case is 14 x 11 cm.
Tomasz Gancarczyk made one too: http://www.grasshopper3d.com/photo/knob-controller
and so did bingg http://www.grasshopper3d.com/photo/arduino-in-use…
here are 11 numbers (0 to 10), and a 'step' of 42 (0 to 42 to 84), and I need to be able to 'cap' the number of times the 11 numbers are added, for example 3 for the list above.
I'm sure this is simple, and I'm kicking myself that I can't figure it out for myself, so any help would be greatly appreciated!…