etc.
Group 2 - 1, 6, 11, 16, 21 etc.
Group 3 - 2, 7, 12, 17, 22 etc.
Group 4 - 3, 8, 13, 18, 23 etc.
Group 5 - 4, 9, 14, 19, 24 etc. "
except in data, the branches start at 0, so 'group 1' is branch 0
as for the order of your points, that depends on the input prior sorting...
yrs …
r example:
{1} {6} Is this possible to do with Replace Branches?
{2} {5}
{3} => {3}
{4} {4}
{5} {5}
{6} {6}
If it were two lists, then it's very easy with List Replace, but kill me, I can't get what's the logic in Replace Branches...
Please help!
…
Added by Artyom Maxim at 10:05am on January 29, 2013
If you right click on the 'Random' component, you will find an option for "Integer Numbers".
You might need to generate random integers of 3, 4, 5 or 6 and multiply that by ten?
a COM error.
I tried to fix the COM with visual studio by updating the references but no luck.
I am currently using rhino 6 because i want to use the new make2d command in grasshopper. But the plug in doesnt work with 5 and 6. same issue.
Have there been any work on this ?
Thank you,
Joey Doherty
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{4}-0;3
{5}-6;7
{6}-5;7
{7}-5;6
Here it can be shown that there are two subgraphs containing 0,1,2,3,4 and 5,6,7. How can I use spiderweb (either using scripting or the components) to give me this result when I have many more vertices??
Thanks,
Sam…