Hi,
I want to divide curve with distance between points so it will be like this:
1--2---3----4-----5------6-------7-----, ...
with values in range 1 to 50, must be simple but im stuck..
tnx
{4}-0;3
{5}-6;7
{6}-5;7
{7}-5;6
Here it can be shown that there are two subgraphs containing 0,1,2,3,4 and 5,6,7. How can I use spiderweb (either using scripting or the components) to give me this result when I have many more vertices??
Thanks,
Sam…
e paths all with 7 points in it for the rest of my list.
For example, if I have 49 points all togethers, I need 7 different paths of 7 points.
Thanks
Maurice…
oning behind using the equality component to test for even numbers is flawed because of the data matching used by gh. It is testing like this:
0==0 True
2==1 False
4==2 False
6==3 False
etc
.............
Where as a Modulo 2 would work like this
0%2 = 0
1%2 = 1
2%2 = 0
3%2 = 1
4%2 = 0
5%2 = 1
6%2 = 0
7%2 = 1
8%2 = 0
9%2 = 1
......
Also I notice you have some errors in your expressions producing Nulls.
If you want it to be twice the value then you should have 2*D in the Expression and 10*D in the other
....
I attach a working version.…
e possible to change the component definition making possible to customize the number of outputs.Now Dispatch moves "true" values to A and "False" values to B
INPUT:
L (List to work on) -> 1, 2, 3, 4, 5, 6, 7, 8
D (Dispatch Pattern) -> True, False
OUTPUT:
A (List) -> 1, 3, 5, 7
B (List) -> 2, 4, 6, 8
Could it be possible/useful to modify it so it could dispatch items to several outputs, like:
INPUT:
L (List to work on) -> 1, 2, 3, 4, 5, 6, 7, 8, 9, 0
D (Dispatch Pattern) -> A, B, C
OUTPUT:
A (List) -> 1, 4, 7, 0
B (List) -> 2, 5, 8
C (List) -> 3, 6, 9
maybe I'm missing something and there's already a component with this function... I have been searching on the forum for half afternoon, but can't find anything about it!
Thank you!…