wunderbar ^^* !
maybe you would be interested in Jun Mitani's work ?
www.flickr.com/photos/jun_mitani/mitani.cs.tsukuba.ac.jhe published two books (keyword : 三谷 純)立体ふしぎ折り紙
ふしぎな 球体・立体折り紙
ght way.
Line no1 and no.2 is the right way for point 0-6
Line no.3 for 7-8
Line no4 for 9-10
Stand 1-3
in the hole project i have 14 lines and 65 points,No number is identical, there is no pattern.
And if i change the beam distance i get more or less points, the lines stay at 14.
Is there a way to count it automatically, i don't want to do it with copy and paste and counting.
solution1 - Maybe that the point knows on which line it is located, or the nearest line.
solution2 - point 0 reads the movement to point 1 if it is the same direction of movement of a line it fits. Line1 = (x+0 y+1 z+1) = point 0 (x+0 y+1 z+1)
point 1 is (x+1 y+0 z-1) so it changes the direction. (i dont know if you can understand my thinking :D)
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iginal from the old forum.
For some reason, I'm getting an error message that the points can't be added to the object list, i didn't have any problem with other types of objects. To fix this, you have to substitute line 65 with this one:
Dim tree As New DataTree(Of on3dpoint)
Btw, as Marc pointed out, this will only work if you are going to output 10 lists or less.…
m in the first place. What would I use to create these sets in a simple object which I can plug everything into. i.e. a mathematical script which uses one number (the number of items in the column). to join every neighbouring pair together. in this case, 21 rows, in 12 columns. Collecting the sets - 1 to 21 with 22 to 43 then 44 to 65 with 66 to 87 etc etc etc.
The selecting curves for the columns are drawn in Rhino, and are all equal in number (in height) as shown in Top view.
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which prohibits any interactive playing with the form.
I'm wondering if a) the tolerance of the component could be relaxed greatly in circumstances like this to enable closer to real-time calculation, and b) if this could be internalized to GH so as not to use the Rhino command line.
Thanks!
Lucas…
the first area and the first number, the second area and the second number and the third are and the third number. For example, let's assume we have the following areas {65, 15, 20}. The absolute difference between these two sets equals {abs(44-65), abs(39-15), abs(17-20)} == {21, 24, 3}. The sum-total of all these absolute differences is your fitness, i.e. 21+24+3 = 48. This number has to go to zero.
If we enter the results you just got, then the absolute differences look like this: {abs(44-44), abs(39-17), abs(17-39)} == {0, 22, 22}, which results in a fitness of 44. Only an exact match will result in a fitness of zero.
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David Rutten
david@mcneel.com
Seattle, WA…
Added by David Rutten at 12:44pm on November 13, 2010