0, 5, 10, 15, 20
1, 6, 11, 16, 21
2, 7, 12, 17, 22
3, 8, 13, 18, 23
4, 9, 14, 19, 24
and if i'm here is because i'm not able... :)
can you help me?
thank you
…
are on their own paths, but the first branch contains 3 curves and the second one 2 curves. If you want the same result for all pairs of curves you'd need to split up the first and second branches, so that all curves are on their own branch.…
Added by Lars Renklint at 4:33am on September 6, 2009
right? When the dataTree is this simple its not really a problem, but when it grows and I want to be able to refer to a specific GH branch e.g. {11;320} and I need to read this specific branch in Python? How do I do this?
I know that there is the function tree.Path(x) this will give me the GH Path, but how do I figure out what x needs to be? I guess there must be a simple answer :).
Thanks Rasmus…
Added by Rasmus Holst at 1:24am on October 14, 2013
13 5 15 6 17 7 ... …
But it seems I have not been clear:
the input values (3,5,7,9,11,13) should be presented in the way of "number slider" parameter. So by increasing the value of the slider from minimum 3, to 5, 7, 9, 13, 15, 17... I should get an output numbers of 0,1,3,4,5,6,7...
So I if choose value 3 on the input "number slider", on the other end, I want 0 as an output.
Or if I choose value 5 on the input "number slider", I want 1 as an output, and so on.
Is this possible?…
otate 9°, the second module 18°, the third 27°, etc. I can only seem to get all 11 modules to rotate the same... I know it probably has something to do with series but I can't figure it out. the screen shot shows the 11 modules rotating to the same degree and the drawing is a plan of what I am trying to accomplish. Thank you so much in advance!…
Added by Daniel Lamm at 6:54pm on September 4, 2014
e now contains (40x3x11=)1320 points with a branch structure of {0-39,0-2} i.e
{0;0}
{0;1}
{0;2}
{1;0}
...
{39;2}
with each branch containing 11 points.
I now want to create lines from the points on line {x;0} to {x;1}, {x;1} to {x;2}, and {x;2} to {x;0}, which will give me a triangular grid on each triangle. How do i do this? I think I need to split the tree 40 times to give me 40 single layered trees but I imagine there's a cleverer way of doing this!
This feel like it should be simple, but I;m having trouble working with the double-layered branch structure. Any help would be greatly appreciated!
Thanks,
Matt…
r surfaces by EP results' components.
Having set a period from 9:00 to 19:00 for a single day (10th december), and using a slider from 0 to 10 (11 values, 0 is 9:00), the following mismatch occurs:
setting value 0 works for surface temperature but not for mean radiant temperature (warning says "stepofSimulation is outside the bounds of the comfResultMTX", but I do have 11 values from radiant temp matrix).
setting value 1 is rendered as "hour 2 of simulation" for surface temperature (FIG 1) and as "9:00" of radiant temperature (FIG 2).
It seems there is a slide of 1 hour. How should I interpret this?
Kind regards,
artemátyika…
Added by artemátyika at 3:34pm on February 2, 2019