o relate to each plane its sections i.e.:
paths=624 - {0;0;2;0}(N=1)
the number of section planes is 70 and somewhere I have 4 section lines and somewhere 5 or 8, is it clear?
1 plane = 1 set of sections
thank you for helping me.…
Added by paul piciorul at 5:35am on October 28, 2010
nch, xno items in one list)2 divide the list lenght value by the numer of items per branch needed3A generate a list with the series component: the step equal to the target numer of items per branch; the no of items equals the number of target branches
3B generate a list with the series component: the first number of the series equals to the number of items needed (-1 to account for the 0 index); the step size again equal to the target number of itmes per branch as 3A4 feed 3A & 3B to a domain component thus identifying the start -3A- and end -3B- of the domains by which the list will be subdivided5 use a subset component with the domains above thus creating 19 branches with lists having 5 items eachfor lists which are subdivided into branches when the target number of branches is not a multiple of the number of items contained in the list:6 identify if the target number of branches is a multiple of the list by using the modulus component fed by the list lenght -1- and the target number of branches7 identify last index in the 3B series with the item component (reversed to take the last value fed)8 add 6+7 above which dill define the start of the domain that will pick up the remanent items not accommodated in 59 add (+1) to 7 above to define the end of the domain that will pick up the the remanent items not accommodated in 510 feed 8 & 9 to a domain component11 include 10 as part of the subset in 5I'm now trying to understand the components mentioned by Michael...
sn
…
r itself is compiled against .NET 3·5.
I recommend you use Rhino4, .NET 3·5 and VS 2008 as a debugging platform.
--
David Rutten
david@mcneel.com
Poprad, Slovakia…
Pérez Albà McNeel Europe presents Rhino 5.0, Matus Nedecký (flying architecture) and Fabio Palvelli (3D Dreaming) show VRAY for Rhino and rendering services for architecture. We also show the new Wacom Cintiq 22 HD touch.
There are 2 events, the first at 15:00 and the second at 18:30. Places are limited to 30 people each.
As a special event you can switch between the events at a basic coffee seminar "Coffee - from the plant to the cup" part. Coffee Museum in Austrian society and economy museum was founded by Edmund Mayr, who injected together with Arch Wilhelm Holzbauer, the increase of the flak tower in Esterhazy Park. His passion for collecting are also due to the many exhibits that he has collected from all over the world. Additionally Mag. Just shows a quick roundup of "100 Years of Life and Living in Vienna" and how the inventions of Dr. Carl Auer von Welsbach changed the world significantly.
program: 15:00 to 15:45 Presentation software Autodesk Maya 2014 (group 1)
15:45 -. 16:00 Tour "100 years of life and living in Vienna / Dr Carl Auer von Welsbach in the Agricultural Museum (Group 1)
16:00 to 16:45 Presentation software Rhino 5.0 and VRAY (group 1)
5:00 p.m. to 6:15 p.m. basic coffee seminar "Coffee - from the plant to the cup" with Mr Edmund Mayr
18:30 to 19:15 Presentation software Autodesk Maya 2014 (Group 2)
19:15 -. 19:30 Tour "100 years of life and living in Vienna / Dr Carl Auer von Welsbach in the Agricultural Museum (Group 1)
19:30 to 20:15 Presentation software Rhino 5.0 and VRAY (Group 2)
20:15 finger found, drinks and "Come Together"
22:00 End of the event
Participation is FREE, due to the limited number of places but registration is required. To register for the event, we ask you to select the following options:
Online Registration 15:00 http://www.kkkc.at/component/seminar/?task=3&cid=5
Online Registration 18:30 http://www.kkkc.at/component/seminar/?task=3&cid=6
or by email: office@kkkc.at
or Tel: 01-545 78 25…
e
7. True
8. True <-- this one
9. True
10. False
11. True
12. False
13. True
14. True <-- this one
15. True
16. False
17. True
18. False
19. True
20. True <-- this one
21. True
22. False
23. True
24. False
25. True
26. True <-- this one
27. True
28. False
29. True
30. False
31. True
32. True <-- this one
33. True
Any idea how I can solve this?
Thanks!…
indexes later and the k value is just 5. The goal is to output all combinations of length 5 from the list of integers 0 to 19.
I placed the list in brackets in order to make it iterable (I don't really know what this means.) Somehow I need to get the combinations out of the itertools.combination output.…