a tutti coloro che sono coinvolti. Le lezioni saranno accompagnate in maniera interattiva con esercitazioni che porteranno alla modellazione di edifici di architettura contemporanea, come quelli che trovate al link seguente inerenti ai workshop precedenti* :
Report del workshop con immagini dei lavori svolti e foto
* i modelli potranno subire delle variazioni con nuovi edifici conservando però lo stesso livello di difficoltà
[.]Argomenti:
Teoria:
- modello 3D: finalità, metodi e risultati - Differenza tra i modellatori nurbs e modellatori solidi - Interfaccia di rhinoceros
Tecnica:
- Opzioni di rhinoceros - Linea di comando cambio delle viste - Uso dei livelli - Piani di costruzione - I principali strumenti di modellazione bidimensionale - Selezione degli oggetti - Editing di base - Creazione di superfici - Editing di superfici - Inserimento di immagini - Esportazione di file
-modellazione di un terreno
-modellazione di edifici e padiglioni di architettura contemporanea ( vedi link)
…
or each branch goes to col 1, element 2 to col 2 and so on. The issue I am having is how to deal with branches that have less than 5 elements. Notice how in the attachment the number 8 is at row 2 where I want it to be in row 3.…
Added by jon kontuly at 1:03pm on September 30, 2014
e possible to change the component definition making possible to customize the number of outputs.Now Dispatch moves "true" values to A and "False" values to B
INPUT:
L (List to work on) -> 1, 2, 3, 4, 5, 6, 7, 8
D (Dispatch Pattern) -> True, False
OUTPUT:
A (List) -> 1, 3, 5, 7
B (List) -> 2, 4, 6, 8
Could it be possible/useful to modify it so it could dispatch items to several outputs, like:
INPUT:
L (List to work on) -> 1, 2, 3, 4, 5, 6, 7, 8, 9, 0
D (Dispatch Pattern) -> A, B, C
OUTPUT:
A (List) -> 1, 4, 7, 0
B (List) -> 2, 5, 8
C (List) -> 3, 6, 9
maybe I'm missing something and there's already a component with this function... I have been searching on the forum for half afternoon, but can't find anything about it!
Thank you!…
output will show a tree with 3 branches of 4 integers each that I can pass on to other components. What is the best way to do it?
I have tried creating a tree and using a for loop to do so, but it didn't work.
Thank you for your help.
…
rve
10 curve
11 curve
12 curve
13 curve
...and I'd like to rearrange the order in which the curve are listed, to something like this:
{0,0,0}
0 curve
1 curve
8 curve
9 curve
10 curve
11 curve
2 curve
3 curve
4 curve
5 curve
12 curve
13 curve
6 curve
7 curve
I hope this makes sense.
Thank in advance for any advice,
John…
the one-but-last list [4]. After running out of the n- items avalaible it should continue with the second item of list 0 and so on for all items on all the lists.
Intput, six lists of 30 items each
[0] (n=30)
[1] (n=30)
[2] (n=30)
[3] (n=30)
[4] (n=30)
[5] (n=30)
Output, 18 lists of 10 items each
[0],i=0;[5],i=4; [4],i=7;...
[0],i=1;[5],i=5; [4],i=8;...
...
[5],i=1;[4],i=5; [3],i=0;...
I thought perhaps the weave component or the relative tree item component but didn't manage to figure out how to compose the mask. I couldn't find much on how to use these. I guess it should wrap the lists, but not the items.
Any help would be greatly appreciated.…
Added by Thorsten Lang at 2:27am on January 24, 2011