hink you need recursion to modify the random seed; many other ways to accomplish that (use the length of each curve as the seed, for example).
Using multiples of twelve makes it harder for me to grasp the essence of the matter; another way of looking at it is that you want to generate random integers from 2 to 5 (24,36, 48 and 60) and have them add up exactly to curve lengths of 5 (x12=60), 9 (x12=108) or 14 (x12=168).
So you want to generate random numbers until their sum ('Mass Addition') plus 5 is equal to or greater than the curve length (5, 9 or 14). The last number in the series is then not random but just the difference between the two.
For example, for curve length = 5 (x12=60), there are only three possible numbers that can be used as the first in the sequence: 2, 3 or 5. If it's 5, you're done. If it's 2, the second number is 3 (5-2), if it's 3, the second number is 2 (5 - 3). You can't use '4' at all because the remainder, 1 (x12=12) isn't one of your solution options.
There is no point in generating the last number randomly, eh?
P.S. You didn't use 'Internalize data' for the 'Curve (Crv)' param in your GH file.…
Added by Joseph Oster at 2:29pm on September 12, 2015
n Continue For
End If
Next
actually for performance issue, I should put "the continue for " on the first:
Dim i As Integer
For i = 0 To 9
If x <> 3 Then Continue For
If x = 3 Then
print("The number is 3.")
End If
Next…
lections import defaultdict
example_list = [[1,2,4], [1,2,3], [3,4,3], [1,2,3], [5,7,1], [3,4,3], [5,7,1], [1,2,4], [9,4,9], [9,3,9], [9,4,9]]
d = defaultdict(list)
for item in example_list: d[tuple(item)].append(item)
groupedlist = sorted(d[x] for x in d)
print groupedlist
# Returns [[[1, 2, 3], [1, 2, 3]], [[1, 2, 4], [1, 2, 4]], [[3, 4, 3], [3, 4, 3]], [[5, 7, 1], [5, 7, 1]], [[9, 3, 9]], [[9, 4, 9], [9, 4, 9]]]
____________________________________________________
However working with python inside GH the code fails as (I'm assuming the id is included in the list ie.
[<Rhino.Geometry.Point3d object at 0x0000000000000BD0 [1611664.12669822,2952929.94466619,5788.70761766478]>]
If I print my object[0] i get just the vector, i.e [1611664.12669822,2952929.94466619,5788.70761766478]
However if i append my object, (for i in xrange (len(X)... list.append(my object[x])
The id included!?
[<Rhino.Geometry.Point3d object at 0x0000000000000BD0 [1611664.12669822,2952929.94466619,5788.70761766478]>]
Perhaps I'm over complicating this and should just use GH to group objects with the same position...
Also sometimes when getting vectors I receive long numbers such as.. 9.0122222900391e(10), and another times I don't.... Same file, script, geometry etc..
I'm quite a noobie in python for GH so any help or pointers are welcome...
Thank you in advance!
…
53 → 53 → 63 → 74 → 74 → 84 → 9
As you can see from the above list the connection sequence comes in waves of three, where each group of similar indices on the left is associated with a group of three incrementing indices on the right.
Some combination of Series components will probably generate this list, but it'll only work for the first ring, the second one will need a different connection pattern. It is perhaps better to just encode the integer pairs by hand. But then you cannot change your mind about the number of sides later.…
Added by David Rutten at 10:39am on October 21, 2015
a follow up question... how do I wrap a list onto itself at a certain frequency?
i.e. I want the list {1;2;3;4;5;6;7;8;9}
to become {1,4,7; 2,6,8; 3,6,9} wrapped every 3rd item
Added by Joshua Jordan at 5:30pm on November 17, 2012
Hi,
in this moment I can't understand the table.
I have two list A and B both with 3 item, so I have 9 combinations. why the table has 4 column and not 3?