ll these 12500 points.
Group 1 would represent the point located at 0, 5, 10, 15, 20 etc.
Group 2 - 1, 6, 11, 16, 21 etc.
Group 3 - 2, 7, 12, 17, 22 etc.
Group 4 - 3, 8, 13, 18, 23 etc.
Group 5 - 4, 9, 14, 19, 24 etc.
I can create the pattern but the selection of points are all the points in row 0 and then all the points in row 5 and so on.
I would like the selection of points to start at the bottom left, and sequentially continue to the right and then continue on the 2nd row (left to right & bottom to top). i am hoping the pattern i am trying to achieve is more understood with the quick screen capture I uploaded.
the end goal is to be able to select all the points in the grid that are in each pattern.
Thanks in advance for any guidance with this. …
Added by Alyne Rankin at 6:53am on October 11, 2017
.
At that rate, 1327 buildings would take ~18 hours!!! Ouch.
I wonder if swapping the loops is any faster? Once through the buildings and 1327 times through the list of hours?
Results for 100 buildings attached - do they match the data you have?…
Added by Joseph Oster at 2:29pm on January 18, 2016
ue vão possibilitar a criação de formas mais complexas, dinâmicas e paramétricas.
http://www.rhino3dportugal.com/website/?portfolio=grasshopper.…
Added by Brimet Silva at 7:32am on January 16, 2012
ng (It's a bit similar to the Knapsack problem):
I have a Variable --> XandI Have fix numbers (can we call "pieces") 9,12,15,18
I'd like to reach the X, with the summing of these numbers and using the minimum pieces ,it can't be lower than X, but it can be higher, maximum with 3.After this it has to found the most optimal combination which mostly use the same pieces
E.G.
X=98
The wrong solution is like = 1pcs of 18 = 9pcs of 9
Sum of pieces are 10
OR
= 3pcs of 18 = 1pcs of 15 = 1pcs of 12 = 2pcs of 9
Sum of pieces are 7
The right solution in this case = 5pcs of 18 = 1pcs of 9
(5*18)+(1*9)=99 it's good beacuse it's over with maximum 3 and uses the minimum pieces
Then it sends to a list like18 : 5pcs15 : 0pcs12 : 0pcs9 : 1pcsCan somebody help me ? Or is it possible to make this ?
Thank you…
Added by Petrik Kollár at 1:09am on November 10, 2017
I've attached a rh and ghx file. http://we.tl/ghsd0UTxji - wetransfer link. I'm guessing the trick is to correctly define the Range (R) / Domain in the Random component, so that the circles' radi can vary between the fixed and static domain of 10 or 12 or 14 or 18 or 20. Meaning that the radi can only be 10, 12, 14, 18 or 20 - and not, lets say.. 11, 13, 15, 16, 17 or 19 for that matter. Thanks in advance, i hope someone can figure it out, because i can't seem to find anything online about how to set up such as specific domain.
…
掌握编程过程中遇到的思路方面和技术方面的问题. 内容包括以下几个方面:
反向逻辑思维能力的培养;
建立清晰的编程逻辑思维能力;
GH 的程序设计理念;
并行数据结构深入理解和控制.
Grasshopper course of McNeel Asia focus on the cultivation of students flexible use of programming techniques, the ability to solve practical problems. Our course deep into the whole process of programming, from programming thinking model, the components principle to usage details do detailed explanation, help students complete mastery programming encountered in the process of thinking and technical aspects, include the following content:
Ability of reverse logical thinking;
Establishment of clear programming logical thinking ability;
The program design concept of Grasshopper;
Understanding parallel data tree structure and how to control it.
更多详细内容... More details…
授课讲师 Instructor 课程由Grasshopper原厂McNeel公司在中国地区的两位 Rhino 原厂技术推广工程师 – Dixon、Jessesn联合授课。课程结束后对达到授课预定目标的学员颁发唯一由Grasshopper原厂认证的结业证书.
Dixon & Jessesn, McNeel Asia Support engineer, by the end of course student who achieve the intended target will get the authentication certificate from McNeel Asia.
课程报名 Register this course 课程即日开始报名, 开课一周前停止报名, 名额满提前报名结束. This course begin to sign up, stop sign up a week ago, with the quota ahead over.
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课程日期 Schedule 7/15-7/20 Beijing 北京 7/26-7/31 Shanghai 上海 7/07-7/12 Shenzhen 深圳
课程范例演示 Samples of Grasshopper course demo
Note: pls follow below comments by Jessesn to see the samples…
m for example) meshing would be a good answer (if it works) - i tried the mesh options min/max edge but that didnt really work for some reason (my guess is the long diagonal edges ruined it but im not sure)hope it is possible, a project depends on itThanksG …
Added by Guy Austern at 2:44pm on October 17, 2010