uld be much better than Rhino at huge mesh collections. I'd personally try free Autodesk Meshmixer and ZBrush first but most designers are more familiar with rendering programs like Maya or 3DS Max. I'm not familiar enough with architecture to suggest a list as only Revit and Sketchup come to mind.
Looking more closely, CAD Exporter is only for 2D curves and points, how silly, and it requires baked geometry in a Rhino layer:
I could write a Python script to export an STL but that would be a large ascii format file instead of binary. Better to use OBJ to retain quad faces, too.
Ah, well, OBJ files are also ascii format when exported from Rhino, so it would be quite easy to make a script to export those directly to disk from Grasshopper. Here is one box, 10X10X20 in size, with quad faces:
# Rhino
o object_1v 10 10 20v 10 10 0v 10 0 20v 10 0 0v 0 10 20v 0 10 0v 0 0 20v 0 0 0f 5 7 3 1f 5 6 8 7f 3 7 8 4f 2 4 8 6f 5 1 2 6f 3 4 2 1
If I have time I'll make a little script to write such OBJ files unless you can find a native Grasshopper plugin for direct OBJ export in full 3D for meshes.…
0;3} (N = 2)
{0;0;0;4} (N = 2)
{0;0;1;0} (N = 2)
{0;0;1;1} (N = 2)
{0;0;1;2} (N = 2)
{0;0;1;3} (N = 2)
{0;0;1;4} (N = 2)
Flattening this structure using the Flatten component would result in:
{0} (N = 20)
However, using a Path Mapper with the following masks will flatten is somewhat more intelligently:
{A;B;C;D} -> {A;B;C}
Now, you get:
{0;0;0} (N = 10)
{0;0;1} (N = 10)
--
David Rutten
david@mcneel.com
Poprad, Slovakia…
Added by David Rutten at 3:19am on December 14, 2009
SiTI - Politecnico di Torino + ETH Computational Assessment Workshop at ETH - ValueLab - March 20, 2012 Assessment of 3 scenarios on the development of the F...
square units. Then you have an integral number of fragments on each side. This means that if all fragments need to have the same surface area, you can only have the following possibilities for side A:
1 fragment = 100 square units
2 fragments = 50 square units each
3 fragments = 33⅓ square units each
4 fragments = 25 square units each
5 fragments = 20 " "
6 fragments = 16⅔ " "
etc.
For side B, the numbers are mostly different
1 fragment = 300 unit²
2 fragments = 150 unit²
3 fragments = 100 unit²
4 fragments = 75 unit²
For side C they are different still. Unless you join fragments across on both sides of the edges of the box, I very much doubt you'll be able to pull this off.
The solution I attached will create fragments as identical as possible, but it's a very boring outcome...
--
David Rutten
david@mcneel.com
Poprad, Slovakia…
I would now like to do is "combine" (only count once) the panels that are stacked vertically between the domain. (I've only got 3 surfaces selected to cut down on the confusion)The domain is the horizontal lines on the object to the ground plane. so Level 1 is 0-8'-7 3/4". Level 2 is 8'-7 3/4" - 15'-3 3/4". ect.
The approach is that the panels that are stacked on top of each other have the same x,y coordinate so they can be separated and counted as 1 instance in the final count.
I started trying to deconstruct the points and create sets of each x and y value but I've got no idea where to go from there. Any have any ideas?
Excel File being referenced looks like this:
Ground
0
1
8.6458
2
15.0625
3
22.375
4
28.5
5
35.333
6
42.2708
…
s and..set of 25 points?.."= when my 2 surfaces points(xyz coords) are written to XL i assumed the one with 30 points would take up more "cells"(longer columns) in XL than the set with 20. So yes, i am for example trying to interpolate between 2 sets of points one with 30+ points and one with 25+ points,."..just rotate it back 90 degrees using the "rotate" function.."= tried that 1st, but although it rotated the Patch it did not correct or affect Copy Trims errored rotation,.I'll prep and upload my def. if you like?,
Thanks for reply & suggestions,
Jeff…