- 100.
After that, I want to separate it into 5 different lists in spesific thickness.
in this case of 0-100 so it would be :
1. if the distance 0 - 20 then the thickness is 5
2. if the distance 21 - 40 then the thickness is 10
3. if the distance 41 - 60 then the thickness is 15
4. if the distance 61 - 80 then the thickness is 20
5. if the distance 81 - 100 then the thickness is 25
But, the problem is the list of distance isn't static between 0-100. It could be 5 - 250 / 3.5-175/etc.....
Could you help me how to make the expression?? Is this possible if I make one expression?
thank you.
Z.
nb: distance and thickness hasn't mathematical relation.…
Added by ZAQI FATHIS at 8:43am on November 27, 2013
angle has to be between 5° to 15°
-for color 2, the angle has to be between 20° to 30°
etc..
Can I subdivided the surface by type of color (exemple: color 1 will be 2 subdivision; color 2 will be 3 subdivision, ..)
many many thx for your help guys :)
…
s suivantes
{0;0} {0;0}
0=longueur (300) 0=longueur (400)
1=largeur (8) 1=largeur (6)
2=hauteur (20) 2=hauteur (8)
{0;1} {0;1}
0=longueur (250) 0=longueur (250)
1=largeur (8) 1=largeur (8)
2=hauteur (12) 2=hauteur (12)
{0;2} {0;2}
0=longueur (400) 0=longueur (300)
1=largeur (6) 1=largeur (8)
2=hauteur (8) 2=hauteur (20)
je souhaite réorganiser mes listes en fonction de la croissance de l'item 1 (soit la largeur) puis en fonction de l'item 2 (la hauteur) néanmoins pour chacune de ces listes les items sont indissociables .
dans l'exemple de gauche la liste de rhino et dans l'exemple de droite la liste que je souhaite obtenir c'est d'abord la largeur qui va croissante puis ,lorsque les largeurs sont identiques ce sont les hauteurs qui vont dans l'ordre croissant .Les longueurs restent assignées à la liste.…
om frame -5 till frame -10 a frame spacing of 100mm is used,
etc.
Frame 0 is located on X=0 mm
Frame -5 will be on X=-500 mm
Frame -6 will be on X=(X of frame -5) -25 = -525 mm
Frame -11 wil be on X= ((X of frame -10) -10 = ?? mm
etc.
Cheers,
Bas…
which doesn't exist in the actual problem spec. If galapagos is allowed to change the column position in all possible directions, it is less likely to get stuck in some local optimum.
Let's assume that (all other things being equal) column 20 would yield the best possible answer. The current state of the system though is at column 26, which is pretty good too, just not as good. Galapagos is more likely to 'mutate' the state a little bit instead of a lot, so it'll explore the columns near 26. However 20 isn't near 26 at all, only 25 and 27 are nearby, and maybe 24 and 28. But they'll all worse answers, so after sampling in those directions GP will abandon that as fruitless.
If however you specify the columns using two variables, then the columns near 26 are 20, 25, 27 and 32. That's a far richer space to explore which much better approximates the real problem.…
rph)
Thus I need an interval grabbing these elements from 0 to 2, from 3 to 5 and so on. Now is just a matter of using two series components and basic maths to fill this interval with the proper numbers.
See attached image for further detail…
7,8. It would plot on the line of the 20%, 20%, 70%, 80% of the length of the line. I'm not looking for a way to divide the curve by 2 and then by 2,not steps. So I would have two points at 20%. I hope this is clear.
Thanks,
Tom…
ut no luck so far...
and for some reason, the number of curves in the lists is double what I think it should be... for instance, if I create a series of 20 curves (20 stories of the building), the output at the end of the definition says "40 locally defined values" ... not sure if this is a problem...…