wunderbar ^^* !
maybe you would be interested in Jun Mitani's work ?
www.flickr.com/photos/jun_mitani/mitani.cs.tsukuba.ac.jhe published two books (keyword : 三谷 純)立体ふしぎ折り紙
ふしぎな 球体・立体折り紙
circles that can be populated (for each radius size) is set as an integer (or slider)
(ie. radius 1.5 = 10 , radius 3= 6, radius 6 = 6, radius 9=4)
Conditions are:
1) Each of the circle has a radius of influence,
Radius of influence = double the radius of the circle)
(3, 6, 12, 18)
2) Any overlapping circles in either: Radius of influence or the Circles are removed so that
No circles overlap.
3) There must also be 4 circles set at the corner points of the grid - These must be circles with a radius of 3 or 6
If you can do that I will be amazed as i've been trying for weeks! :(
Ive attached a sketch of what im looking for…
you want each "element" to be a single Item or a single item for ALL elements. See Below
0. 20
1. 30
2. 59
3. 60
4. {9,45,29}
5. 0.0
6. 3.0
7. 6.0
Or
0. 20 30 59 60 {9,45,29} 0.0 3.0 6.0
…
Added by Danny Boyes at 3:13am on October 29, 2013
1#comments
But I seem to be having a problem with this closest to some value thing: values in my list are too small, up too 1 x 10^-30. The closest value I want to search for in that list is 1.25 x 10^-9
But Grasshoppers "find similar" component recognizes all of the values from the list, to be similar to 1.25 x 10^-9, because all of those values are in range from 0.1 to 1 x 10^-30.
Is there a way some kind of tolerance can be made, when it comes to recognizing a similar value?…
cture, Rhino treats them as a single flat list. For example a surface can have 10 rows and 6 columns of control-points, resulting in a list of 60 points.
But 10 times 6 isn't the only way to get to 60. If you want to make a surface out of a list of 60 points, you'll also have to tell Rhino how those 60 points should be interpreted in terms of a grid. It could be 2*30, 3*20, 4*15, 5*12, 6*10, and all of the aforementioned products the other way around.
Sometimes there's only one way for a number of points to fit into a rectangular grid. For example if you provide 49 points, then 7*7 is the only way to make it work, but these cases are rare so we always demand you give us all the information required to actually make a rectangular grid of control-points from a linear collection.
As for "Why is it, sometimes we need to attach additional value into it?", this is usually because when you divide a domain or a curve into N segments, you end up with N+1 points. For example take the domain {0 to 5}, and divide it into 5 equal subdomains. You end up with {0 to 1}, {1 to 2}, {2 to 3}, {3 to 4} and {4 to 5}. However there are six numbers that mark the transitions between these domains 0, 1, 2, 3, 4 and 5. This is why you often have to add 1 to the UCount, because the number that controls the UCount often results in N+1 actual points.…
Added by David Rutten at 8:30am on December 25, 2014