so the list actualy looks like this:
0 5
1 10
2 15
3 20
4 25
....
Is above possible? and insteed of doing this "a manual way" would it be possible with a function? Sometimes there might be 9 rows sometimes only 7 rows.…
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e material I want.
There are some command I don't understand inside the csv file, just wonder if you know how to read time and edit them?
e.g. for the data of concret :
#;;;;;;;;#;;;E;G;gamma;alphaT;fcd;my#;family;name;[kN/cm2];[kN/cm2];[kN/m3];[m/(mC°)];[kN/cm2];[-]#;"according to EN 1992-1-1; revision 2009-07-01:";;;;;;;;Concrete;Concrete;3100;1291.67;25;1.00E-05;1.67;0.2;Concrete;C12/15;2700;1125;25;1.00E-05;0.8;0.2;Concrete;C16/20;2900;1208.33;25;1.00E-05;1.07;0.2;Concrete;C20/25;3000;1250;25;1.00E-05;1.33;0.2;Concrete;C25/30;3100;1291.67;25;1.00E-05;1.67;0.2;Concrete;C30/37;3300;1375;25;1.00E-05;2;0.2;Concrete;C35/45;3400;1416.67;25;1.00E-05;2.33;0.2;Concrete;C40/50;3500;1458.33;25;1.00E-05;2.67;0.2;Concrete;C45/55;3600;1500;25;1.00E-05;3;0.2;Concrete;C50/60;3700;1541.67;25;1.00E-05;3.33;0.2;Concrete;C55/67;3800;1583.33;25;1.00E-05;3.67;0.2;;Concrete;C60/75;3900;1625;25;1.00E-05;4;0.2;;Concrete;C70/85;4100;1708.33;25;1.00E-05;4.67;0.2;;Concrete;C80/95;4200;1750;25;1.00E-05;5.33;0.2;;Concrete;C90/105;4400;1833.33;25;1.00E-05;6;0.2;#;;;;;;;;;
DO you know what does [#;;;E;G;gamma;alphaT;fcd;my] stand for? what is E? G? gamma? alphaT? fcd? my? I know I need to find the according data for my specific material but I am not sure what they mean.
Thank you very much…
n I'll tell you. Either way we used WeaverBird in the earlier stages of development whereas Weaverbird's Laplacian Smoothing became really useful.
http://smartgeometry.org/index.php?option=com_community&view=groups&task=viewgroup&groupid=25&Itemid=0
http://vimeo.com/39440746
//Oliver :-]…
square units. Then you have an integral number of fragments on each side. This means that if all fragments need to have the same surface area, you can only have the following possibilities for side A:
1 fragment = 100 square units
2 fragments = 50 square units each
3 fragments = 33⅓ square units each
4 fragments = 25 square units each
5 fragments = 20 " "
6 fragments = 16⅔ " "
etc.
For side B, the numbers are mostly different
1 fragment = 300 unit²
2 fragments = 150 unit²
3 fragments = 100 unit²
4 fragments = 75 unit²
For side C they are different still. Unless you join fragments across on both sides of the edges of the box, I very much doubt you'll be able to pull this off.
The solution I attached will create fragments as identical as possible, but it's a very boring outcome...
--
David Rutten
david@mcneel.com
Poprad, Slovakia…
ake them appear
2. Also I haven't been able to trim the boxes on these edges
3. I want to randomly select and group a percentage of the boxes, having at the end 2 groups of boxes (i.e. 25% and 75%).
I will appreciate if someone can help me with this.…
and 1000 ms cut-off time, it takes pachyderm about 20 minutes on my computer. On the same computer, it takes EASE just a few seconds to run that model.
There has to be something off that I'm missing. Does Pachyderm use all available cores by default or do I have to activate multi-core processing somewhere?…