iders that control the total amount ( U&V) and the branches are formed by picking i.e the U and the points will then be the number on the V slider...
I realize that this question may have been asked before, but I cannot solve it with the path mapper and it seems so easy
M…
another comma separated txt file. I know how to import points (function Import coordinates), but I dont know how to connect them by lines if the only information I have about lines is the list of point numbers which should be connected. The txt file with point coordinates looks like:
-18,-36,-1000-18,-34,-19.728-18,-32,-17.603-18,-30,-15.372-18,-28,-13.121
...
And the txt file with line connections looks like:
1,22,33,44,55,6
...
Which means that I want to connect point 1 with point 2, point 2 with point 3 etc...
Both txt files are attached, thank you for the answer...…
byte-accuracy red, green, blue channels) = 27 bytes. More likely 28 bytes as colours are probably stored as 32-bit integers, allowing for an unused alpha channel.
28 * 800,000 equals roughly 22 megabytes, which is way down from 9 gigabytes. That's a 400 fold memory overhead, which is pretty hefty.
Grasshopper stores points as instances of classes, so on 64-bit systems it actually takes 64+64+3*8 = 152 bytes per point*, which adds up to 122MB, still way less than 9GB. It would be interesting to know where all the memory goes...
* Grasshopper points also store reference data, in case they come from the Rhino document. This data will not exist, but even so it will require 64-bits of storage.…
Added by David Rutten at 4:13pm on December 11, 2014
ctorial component to go to higher factorials/permutations just to determine easily permutations. For instance I have 30 tile colors and I wanted to see their permutations quickly, I realize I can use 30*29*28 etc but I thought I could do this using the simple definition that one can see in the pic.
RM
…
vas
Closing and creating a new file (memory resets when this is done) @4:00, 5:57, 6:53
System slow down and crashes @ 8:16 (takes 5 minutes to end the process - perhaps not the most entertaining movie to watch until the end - a good point to turn the kettle on)…
es, and these sum up to ~7100. I shall see if I can post a screenshot of everything.
I have no idea how to script that, sorry. But maybe could be a more optimized workflow - just feed one object B at a time, maybe that makes the math behind it more relaxed.
I should emphasize that it is not about 'fault' in the operation, and rather a very slow calculation - the difference does eventually get calculated with no errors whatsoever, the only problem is the unbelievably inefficient, or unproductive time it takes to do so. I think the problem could be the proportion of the objects, one very large, and one very small (28 / 6 / .1cm vs. .05cm), maybe that does something funky to the bounding box calls, I have no idea. And one other thing I suspect is the number of faces in the object, as I progress to let's say 700 cuts, I have then created 700*4 new faces in the object. I don't know if this is indeed something of concern. …
Added by DumDaDaDum at 7:03am on September 29, 2011
g it still dose not bake.
Sub RunScript(ByVal Points As List(Of Object), ByVal GridName As String, ByVal Bake As Boolean, ByVal Num As Integer)
If( Not Bake ) Then
m_count = 0
Return
End If
'Iterate through points by row
Dim i As Integer
Dim j As Integer
j = 0
For i = 0 To Points.Count() – 1
If( j > Num + 1 ) Then
j = 0
End If
Dim pt As On3dPoint
pt = Points(i)
'Name the point
Dim att As New On3dmObjectAttributes
doc.GetDefaultObjectAttributes(att)
att.m_name = GridName & "(" & m_count & ")(" & j & ")"
print(m_count)
'increment index
j += 1
'Add to document
doc.AddPointObject(pt, att)
Next
m_count += 1
A = m_count
End Sub…
he installation folder, Drag & drop SYNTACTIC(green one) over your grasshopper canvas.3. Close your rhino and reopen it. 4. Type GrasshopperDeveloperSettings5. Tick the Memory load *.GHA assemblies using COFF byte arrays option6. Run grasshopper and enjoy plugin…