of Data. The Data can be Single Items or Lists of Items. Your example above is a Tree with 2 Branches of 6 Items. Each Branch is a List of 3 Lines. using the Flip Matrix component will result in a Tree with 3 Branches of 6 Items. Each Branch would be a List of 2 Lines.…
do is take the list of duplicates and convert them into a boolean pattern so that i can dispatch the original list of points (pre-cull operation). specifically, i want to replace all instances of 3 with 3 true values, and all instances of 6 with 6 false values. any ideas?…
Added by Seb Sarrazin at 3:42am on February 7, 2013
thanks for the quick reply.I have version 0.9.0014 and your file is not compatible.perhaps I have not explained well: I have to drill a rectangle to 50% with 3 holes.excuse my English.thanks again
Your original tree contains 3 items, your desired three contains 9 items. Where do these 6 new items come from?
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David Rutten
david@mcneel.com
Poprad, Slovakia
between internal structural frameworks and non-bearing skin elements, this approach promotes heterogeneity and differentiation of material properties. The project demonstrates the notion of a structural skin using a Voronoi pattern, the density of which corresponds to multi-scalar loading conditions. The distribution of shear-stress lines and surface pressure is embodied in the allocation and relative thickness of the vein-like elements built into the skin. Its innovative 3D printing technology provides for the ability to print parts and assemblies made of multiple materials within a single build, as well as to create composite materials that present preset combinations of mechanical properties.
for registration please contact:
bioskinarc@gmail.com
tel: 09197804306
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I'm trying to retrieve data from a tag heuer timing system through rs 232. Firefly ports available says com ports 1 and 3 are available. Is one of those two the rs 232 9 pin? Thanks for your help.
{4}-0;3
{5}-6;7
{6}-5;7
{7}-5;6
Here it can be shown that there are two subgraphs containing 0,1,2,3,4 and 5,6,7. How can I use spiderweb (either using scripting or the components) to give me this result when I have many more vertices??
Thanks,
Sam…
etc.
Group 2 - 1, 6, 11, 16, 21 etc.
Group 3 - 2, 7, 12, 17, 22 etc.
Group 4 - 3, 8, 13, 18, 23 etc.
Group 5 - 4, 9, 14, 19, 24 etc. "
except in data, the branches start at 0, so 'group 1' is branch 0
as for the order of your points, that depends on the input prior sorting...
yrs …