0, 5, 10, 15, 20
1, 6, 11, 16, 21
2, 7, 12, 17, 22
3, 8, 13, 18, 23
4, 9, 14, 19, 24
and if i'm here is because i'm not able... :)
can you help me?
thank you
…
dont get you, i am saying sleect numbers in range 1 to 10, starting from 1 with a step of 2.
1 to 10 by 3 = 1 4 7 10
1 to 10 by 5 = 1 6
1 to 10 by 1 = 1 to 10 = 1 2 3 4 5 6 7 8 9 10
Added by Steve Lewis at 3:15pm on November 11, 2013
eam then use the tree branch component with a path that is automated to the number of data streams i have (say using the tree statistics component) to link up with a line component. So far I have failed in doing this because I cannot seem to make a 6 branch tree.
…
formula says "Syntax error: Right hand value of operator ( is Null."
Any insights into why the formula isn't working?
Here is the formula that is plugged into the y-coordinate:
(-1/15)*Sin(u)*(3*Cos(v)-3*(Cos(u))^2*Cos(v)-48*(Cos(u))^4*Cos(v)+48(Cos(u))^6*Cos(v)-60*Sin(u)+5*Cos(u)*Cos(v)*Sin(u)-5*(Cos(u))^3*Cos(v)*Sin(u)-80*(Cos(u))^5*Cos(v)*Sin(u)+80*(Cos(u))^7*Cos(v)*Sin(u))
Here is the link to Wikipedia to see the formula:
https://en.wikipedia.org/wiki/Klein_bottle
Thanks for your time,
August…
ep is to understan the logics of what you want to do, in your case, build 4 point surfaces (u also need to know the right direction to build the surfaces). Then you can write an hipotetic list (by hand in a paper) of what you want. In your case the list was (0, 1, 3, 2) (2, 3, 5, 4) (4, 5, 7, 6), etc... if you can imagine building 2 lists, each one with the sequences (0, 2, 4, 6, etcc) and (1, 3, 5, 7, etc..) then you can manage with shift and graft to finally have four lists. A( 0 1 2 3 ...) B (1 3 5 etc..) C(3 5 7 etc..) D (2 4 6 etc..). And to achieve the 2 first lists, you need to get the odd and the pair numbers. The cull pattern does that amazingy well. With a pattern True-False you get de pair numbers, and with the False-True pattern you get de odd numbers.
Hope it was clear enough…
Added by Pep Tornabell at 5:32am on November 19, 2009