5 chunks ->
1 chunk with all items that divide circle into 3 parts.
2 chunk with all items that divide circle into 4 parts.
3 chunk with all items that divide circle into 5 parts.
etc. until items that divide circle into 7 parts.
Hope you can understand my problem.
I added image of definition below.
Thanks!
…
nd this is the error text:
0. Current document units is in Meters1. Conversion to Meters will be applied = 1.0002. [1 of 8] Writing simulation parameters...3. [2 of 8] No context surfaces...4. [3 of 8] Writing geometry...5. [4 of 8] Writing Electric Load Center - Generator specifications ...6. [5 of 8] Writing materials and constructions...7. [6 of 8] Writing schedules...8. [7 of 8] Writing loads and ideal air system...9. [8 of 8] Writing outputs...10. ...... idf file is successfully written to : C:\Users\Pier\Desktop\Dottorato\Energy_plus_file\cell room\EnergyPlus\cell room.idf11. 12. Analysis is running!...13. C:\Users\Pier\Desktop\Dottorato\Energy_plus_file\cell room\EnergyPlus\eplusout.csv14. ......
Done! Read below for errors and warnings:
15.
Thanks in advance to all for your help me
Francesco…
But say the values you remove aren't consecutive, like if you remove 2, 5 and 7 and want to replace them with values in their original list location...
{0;0;0;0 -1, 2... 19 ) N=5
i know is basic but im still trying to get my head around lists/trees and how to manipulate them properly
thanks for your time
sn…
cture, Rhino treats them as a single flat list. For example a surface can have 10 rows and 6 columns of control-points, resulting in a list of 60 points.
But 10 times 6 isn't the only way to get to 60. If you want to make a surface out of a list of 60 points, you'll also have to tell Rhino how those 60 points should be interpreted in terms of a grid. It could be 2*30, 3*20, 4*15, 5*12, 6*10, and all of the aforementioned products the other way around.
Sometimes there's only one way for a number of points to fit into a rectangular grid. For example if you provide 49 points, then 7*7 is the only way to make it work, but these cases are rare so we always demand you give us all the information required to actually make a rectangular grid of control-points from a linear collection.
As for "Why is it, sometimes we need to attach additional value into it?", this is usually because when you divide a domain or a curve into N segments, you end up with N+1 points. For example take the domain {0 to 5}, and divide it into 5 equal subdomains. You end up with {0 to 1}, {1 to 2}, {2 to 3}, {3 to 4} and {4 to 5}. However there are six numbers that mark the transitions between these domains 0, 1, 2, 3, 4 and 5. This is why you often have to add 1 to the UCount, because the number that controls the UCount often results in N+1 actual points.…
Added by David Rutten at 8:30am on December 25, 2014