some i7 if ECC memory sounds an oddity to you). If the model is big you'll need a decent Kepler Quadro as well ... say a K4200 (I hate game cards including Titan).
http://www.tsplines.com/
Alternatively use a top dog subdivision app (Modo eats them all for breakfast) but that works with DX and that brings us back to game cards.…
thankssssss
.74-.80 may is ok not big differents .. but i have to control each group of triangles :)
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sorry the version is
rhino 4.9
gr 0.8.0004 version
thanks :)
Added by architecture at 6:26am on December 20, 2011
ven if the number of panels inside each cell varies. The current solution works when the number of panels inside each cell is always two or other same numbers, but it wouldn't work if the number of panels inside frames are different in each cell. It would be perfect, if numbering of panels are automatically added correctly next to the cell number based on the number of panel division instead of feeding the fixed number.
To take an example, let's assume that the cell #80 has three panels and the #81 has two ones. In this case, three panels within the cell #80 would be numbered like 80-1, 80-2, 80-3, while two panels within the #81 would be numbered such as 81-1 and 81-2 automatically. …
rence not set to an instance of an object. (line: 80)
Both .dlls appear to have been successfully imported.
Thanks in advance,
Charles
RStatSystem rs = ri as RStatSystem;
List<Line> slines = new List<Line>();
foreach(RStatBeam b0 in rs.Beams) { <------ line 80
if (b0.StiffnessMultiplier < 0.3) continue;
slines.Add(new Line(b0.P0.ToPoint3d(), b0.P1.ToPoint3d())); }
A = slines;
…
ded a circle and been able to draw the two lines and cull out the correct distances but do not know how to pull out those two original lines - the one from the starting point to the circle division + the circle division to the end point.
To recap - I'm looking for a way to have 2 lines = 80" when the direct path between two points is 60". I do not want the 2 new lines to be equal in length but variable lengths.
thanks!
_patrick
…
exact formula is inside /lib/skybright.cal if this can help you to find the name.
{ RCSid: $Id$ } { Sky brightness function for sunny and cloudy skies.
Additional arguments required for calculation of skybright:
A1 - 1 for CIE clear, 2 for CIE overcast, 3 for uniform, 4 for CIE intermediate A2 - zenith brightness A3 - ground plane brightness A4 - normalization factor based on sun direction A5,A6,A7 - sun direction }
cosgamma = Dx*A5 + Dy*A6 + Dz*A7;
gamma = Acos(cosgamma); { angle from sun to this point in sky }
zt = Acos(A7); { angle from zenith to sun }
eta = Acos(Dz); { angle from zenith to this point in sky }
wmean(a, x, b, y) : (a*x + b*y) / (a + b);
skybr = wmean((Dz+1.01)^10, select(A1, sunnysky, cloudysky, unifsky, intersky), (Dz+1.01)^-10, A3);
sunnysky = A2 * (.91 + 10*exp(-3*gamma) + .45*cosgamma*cosgamma) * if( Dz - .01, 1.0 - exp(-.32/Dz), 1.0) / A4;
cloudysky = A2 * (1 + 2*Dz)/3;
unifsky = A2;
intersky = A2 * ( (1.35*sin(5.631-3.59*eta)+3.12)*sin(4.396-2.6*zt) + 6.37 - eta ) / 2.326 * exp(gamma*-.563*((2.629-eta)*(1.562-zt)+.812)) / A4;
…
tries, of different types, both annotation objects and curves, won't it be slow to iterate through all these objects for each rectangle?
I use 0.6.X but i'm soon making the shift to 0.7.X…
ve is most impacted by the characteristics of the vector field...If accuracy is not so important, you can use the curve re-sampling components to create a smoothe curve.…