o three parts:
branch 1:
{0;0} N = 3
{0;1} N = 3
branch 2:
{1;0} N = 5
{1;1} N = 5
branch 3:
{2;0} N = 30
{2;1} N = 30
parthmapper won't change the length of branch, explode tree won't give me two branches in one output
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tion and the points array that follow. I was used to the Rhino.EvaluateSurface(Strobj, ArrParam) to pick pints on a surface.
Then I understand that points are identified with var pt and added with function pt_list.Add(pt) . But can't understand the whole syntax. This code is supposed to create hexagons!
Dim lines As New List(Of OnPolyline)()
'Point Culling
Dim ptArr As New On3dPointArray()
Dim pt_list As New List(Of On3dPoint)
For i As Int32 = 0 To u - 2 Step 2
For j As Int32 = 0 To v - 3 Step 4
ptArr.Append(arrPt(i + 1, j).x, arrPt(i + 1, j).y, arrPt(i + 1, j).z)
ptArr.Append(arrPt(i + 2, j + 1).x, arrPt(i + 2, j + 1).y, arrPt(i + 2, j + 1).z)
ptArr.Append(arrPt(i + 2, j + 2).x, arrPt(i + 2, j + 2).y, arrPt(i + 2, j + 2).z)
ptArr.Append(arrPt(i + 1, j + 3).x, arrPt(i + 1, j + 3).y, arrPt(i + 1, j + 3).z)
ptArr.Append(arrPt(i, j + 2).x, arrPt(i, j + 2).y, arrPt(i, j + 2).z)
ptArr.Append(arrPt(i, j + 1).x, arrPt(i, j + 1).y, arrPt(i, j + 1).z)
ptArr.Append(arrPt(i + 1, j).x, arrPt(i + 1, j).y, arrPt(i + 1, j).z)
Dim pline As New OnPolyline(ptArr)
lines.Add(pline)
Dim pt As New On3dPoint((arrPt(i + 1, j).x + arrPt(i + 1, j + 3).x) / 2, (arrPt(i + 1, j).y + arrPt(i + 1, j + 3).y) / 2, (arrPt(i + 1, j).z + arrPt(i + 1, j + 3).z) / 2)
pt_list.Add(pt)
ptArr.destroy
Next
Next…
Added by Jon Malkovich at 7:16pm on November 3, 2009
g to keep the {15} {16} branch structure because its keeping the organization by floor level.
Any insight into how the Curve Plane Intersection is matching the branches for operation would be helpful as well.
Thanks!
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des]. I have 5-variables with 4 options each (a total of 4x4x4x4x4 = 1024 variations):
Height: 6,7,8 & 9 ft
Depth inside: 1, 2, 3 & 4 ft
Depth outside: 1, 2, 3 & 4 ft
Rotation outside: 0, 15, 30 & 45 degree
Rotation inside: 0, 15, 30 & 45 degree
I do not see convergence yet (see attached). The last combination of variables say 9-ft high, 4-ft deep (inside & outside) and 0-deg rotation (horizontal) inside and outside. Is this the optimized value of the light shelf parameters for the best illumination level at the sensor plane for that specific place, time and date?
Shamim.…
Added by Shamim Javed at 1:01pm on November 3, 2013
t case point 3 should be able to move from 20 to 33
so in other word
pt 3 depends on pt 2
the problem is if i only have sliders
pt2 could be 20
and pt 3 could be 20, that is higher than 33
so the loft loops in itself
gracias por tu ayuda
salu2
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