13 5 15 6 17 7 ... …
But it seems I have not been clear:
the input values (3,5,7,9,11,13) should be presented in the way of "number slider" parameter. So by increasing the value of the slider from minimum 3, to 5, 7, 9, 13, 15, 17... I should get an output numbers of 0,1,3,4,5,6,7...
So I if choose value 3 on the input "number slider", on the other end, I want 0 as an output.
Or if I choose value 5 on the input "number slider", I want 1 as an output, and so on.
Is this possible?…
. The code I wrote up til now is this:
Private Sub RunScript(ByVal x As Double, ByVal y As Double, ByVal z As Double, ByRef A As Object)
Dim pt (2)
pt(0) = x pt(1) = y pt(2) = z
A = pt
End SubDoes anyone know what statement I need to write to make this code work? Kind regardsJasper…
t item (see the image), is it possible to do this in another way (quickly) ?
Is it possible to divide that curve into 2 separate curves using a point that i've used for the division?
Thanks…
Added by luca.pavarin at 4:08pm on January 7, 2010
is passable give different distance in list of point to delete
ex: point 1 - 30
point 2 - 20
point 3 - 10
...........
the point all in one list
i try a lot but didn't found the way ...