9 8 7 6
5 4 3 2 1 0
I am triangulating this surface. I want to select just the red vertices. As you can note, I just need the inner vertices of this surface. I could do it mannually, but if I want to change the mesh density later, I will have to pick all of them manually again later.
Can someone help me?
Tks
…
so the list actualy looks like this:
0 5
1 10
2 15
3 20
4 25
....
Is above possible? and insteed of doing this "a manual way" would it be possible with a function? Sometimes there might be 9 rows sometimes only 7 rows.…
urs x 365 days ), and with modulus in the screenshot above, i could manage to do for every hour. but sometimes in my definition, i have a range from 1 to 35040, which is 365 x 24 x 4 ( 4 here defines every 15 minutes), on other word, when the number is one, then i have 01:00 O'Clock, when the number is 2 then i have 01:15 O'clock, when the number is 3 then i have 01:30 O'Clock...etc , so when the number is 97, which is the next day ( and after the number 96 which is equal 24 hours x 4), then I should have again 01:00 O'Clock.
I hope my idea is clear, thanks in advance!
Nassif…
des]. I have 5-variables with 4 options each (a total of 4x4x4x4x4 = 1024 variations):
Height: 6,7,8 & 9 ft
Depth inside: 1, 2, 3 & 4 ft
Depth outside: 1, 2, 3 & 4 ft
Rotation outside: 0, 15, 30 & 45 degree
Rotation inside: 0, 15, 30 & 45 degree
I do not see convergence yet (see attached). The last combination of variables say 9-ft high, 4-ft deep (inside & outside) and 0-deg rotation (horizontal) inside and outside. Is this the optimized value of the light shelf parameters for the best illumination level at the sensor plane for that specific place, time and date?
Shamim.…
Added by Shamim Javed at 1:01pm on November 3, 2013
to -1 and return -1)
-4th iteration
for Z = 14
return -1 (because 0<Z<15 A is returned and has been set to -1 at the previous iteration)
-5th iteration
for Z=13
return -1
-and so on till
Z=0
return 1 (and set A to 1)
-next iteration
Z=1
return 1
-and so on till we reach 15 and go back the other way
Thanks a lot
…
I would now like to do is "combine" (only count once) the panels that are stacked vertically between the domain. (I've only got 3 surfaces selected to cut down on the confusion)The domain is the horizontal lines on the object to the ground plane. so Level 1 is 0-8'-7 3/4". Level 2 is 8'-7 3/4" - 15'-3 3/4". ect.
The approach is that the panels that are stacked on top of each other have the same x,y coordinate so they can be separated and counted as 1 instance in the final count.
I started trying to deconstruct the points and create sets of each x and y value but I've got no idea where to go from there. Any have any ideas?
Excel File being referenced looks like this:
Ground
0
1
8.6458
2
15.0625
3
22.375
4
28.5
5
35.333
6
42.2708
…
So the distance between each pair of closest points must be exactly 5, 7, or 15? How about the distance between a point and it's 2nd closest neighbour? 3rd closest? ...
Added by David Rutten at 9:41am on November 10, 2017