uld be much better than Rhino at huge mesh collections. I'd personally try free Autodesk Meshmixer and ZBrush first but most designers are more familiar with rendering programs like Maya or 3DS Max. I'm not familiar enough with architecture to suggest a list as only Revit and Sketchup come to mind.
Looking more closely, CAD Exporter is only for 2D curves and points, how silly, and it requires baked geometry in a Rhino layer:
I could write a Python script to export an STL but that would be a large ascii format file instead of binary. Better to use OBJ to retain quad faces, too.
Ah, well, OBJ files are also ascii format when exported from Rhino, so it would be quite easy to make a script to export those directly to disk from Grasshopper. Here is one box, 10X10X20 in size, with quad faces:
# Rhino
o object_1v 10 10 20v 10 10 0v 10 0 20v 10 0 0v 0 10 20v 0 10 0v 0 0 20v 0 0 0f 5 7 3 1f 5 6 8 7f 3 7 8 4f 2 4 8 6f 5 1 2 6f 3 4 2 1
If I have time I'll make a little script to write such OBJ files unless you can find a native Grasshopper plugin for direct OBJ export in full 3D for meshes.…
How are you defining lowest X/Y and highest X/Y? For example, if I have three 2D Points:
{-5, 10}
{-3, 0}
{4, -10}
Which of them qualifies for the highest and which the lowest?
Added by David Stasiuk at 11:36am on February 13, 2016
7, 9, 12 and 13 to be able to rotate freely around the y axis at nodes 2, 3, 6, 7, 10 and 11 respectively. The last 2 conditions, for elements 12 and 13, doesn't give any problems, but the first 4 does.
Any help?
…
to n (I have to catalogate in this way) and of course the result start from 0 to n-1.
How can I change that? I need that the result 10 mach the paramete 10, and not the 11.
Can you help me ?
Regards
Guido…
13;2} ... 20.{13;12}
21. {21;0}22. {21;1}23. {21;2} ... 41. {21;20}
42. {34;0}43. {34;1}44. {34;2} ... 75. {34;33}
76. {55;0}77. {55;1} ... ....
I want to grab the first 8 [0-7], the next 13[8-20], the next 21[21-42] etc
so i have the (known fibonacci seq) list of numbers on the left here:
C S
8 0
13 8
21 21
34 42
55 76
89 131
144 220
233 364
and i need the list on the right, so that i can select items using a Series (N=1 and S and C from the list above) and a List Item component.
the simple question is:
is there a component that can take a list and accumulate it in this way that I need?
if not, is there anyone that can point me to a simple relevant VB example so i could easily adapt it?
many thanks,
gotjosh…
Integer = 0 To 9
val *= 2
lst.Add(val)
Next
Since val is a ValueType, when we assign it to the list we actually put a copy of val into the list. Thus, the list contains the following memory layout:
[0] = 2
[1] = 4
[2] = 8
[3] = 16
[4] = 32
[5] = 64
[6] = 128
[7] = 256
[8] = 512
[9] = 1024
Now let's assume we do the same, but with OnLines:
Dim ln As New OnLine(A, B)
Dim lst As New List(Of OnLine)
For i As Integer = 0 To 9
ln.Transform(xform)
lst.Add(ln)
Next
When we declare ln on line 1, it is assigned an address in memory, say "24 Bell Ave." Then we modify that one line over and over, and keep on adding the same address to lst. Thus, the memory layout of lst is now:
[0] = "24 Bell Ave."
[1] = "24 Bell Ave."
[2] = "24 Bell Ave."
[3] = "24 Bell Ave."
[4] = "24 Bell Ave."
[5] = "24 Bell Ave."
[6] = "24 Bell Ave."
[7] = "24 Bell Ave."
[8] = "24 Bell Ave."
[9] = "24 Bell Ave."
To do this properly, we need to create a unique line for every element in lst:
Dim lst As New List(Of OnLine)
For i As Integer = 0 To 9
Dim ln As New OnLine(A, B)
ln.Transform(xform)
lst.Add(ln)
Next
Now, ln is constructed not just once, but whenever the loop runs. And every time it is constructed, a new piece of memory is reserved for it and a new address is created. So now the list memory layout is:
[0] = "24 Bell Ave."
[1] = "12 Pike St."
[2] = "377 The Pines"
[3] = "3670 Woodland Park Ave."
[4] = "99 Zoo Ln."
[5] = "13a District Rd."
[6] = "2 Penny Lane"
[7] = "10 Broadway"
[8] = "225 Franklin Ave."
[9] = "420 Paper St."
--
David Rutten
david@mcneel.com
Poprad, Slovakia…
Added by David Rutten at 6:26am on September 9, 2010