se presentarán una pieza cortada con láser o CNC.Extracto de TemarioIntroducción Fundamentos Grasshopper Image Sampler V-Ray Interiores Que es es CNCFundamentos Interfase Visualización - Grasshopper V-Ray Exteriores Arboles de datos Corte, Laser e impresión 3dTeoria de Curvas Componentes y parametros Listas de datos V-Ray Materiales Clusters ToleranciasTranspocición Vectores y reticulas -Atractores Series y rangos Teoria de Superficies Conexiones Estrategias de modelado para manufacturaSimetrias Transpocisión parametrica Formulas Panelizacion Teoría de Ensambles Teoría de archivos para corteAtractores Cull Random Información del taller:Fechas: del 8 al 26 de Junio de 2015Sesiones: 8 de 3 hrs y presentación finalDuración: 27 hrs.Días: Lunes,Miércoles y ViernesHorario: de 19:00 a 22:00 hrsPrecio : $4,500 Apartado: $2,000Pago oportuno (antes del 1 de Junio): $3,500PAQUETESTaller y Rhino 5.0 Educativa: $6,500.00 Taller y Rhino 5.0 Comercial: $21,000.00 *Sólo hacemos reembolso en cancelaciones con un mínimo de 15 días previos al taller.info@dimensiontallerdigital.comtel oficina (55) 50160634…
ick OK, the value reverts to zeros for the change in decimal places. (changing from 3 to 6 results in the last 3 reverting to 0)
From that point, re-editing the value works perfectly.
Rhino 4 SR 8 and Rhino 5 1-March
GH 0.8.0007
Win 7 32 Bit.…
ant to find all paths where exactly two items are the same like in branch {1}. How can I solve this in VB? Is there an easy "search in list" class or do I have to iterate over all items by myself ??
Regards Alex…
an't remember it) that will only give you the resulting whole number that results from any given division...modulus division will give the exact opposite, or only the fractions of numbers that result. In code they would be forward slash, back slash, and percent symbol, respectively. That's the case for VB and most other languages as well...here's a simple example...
8/3 = 2.66666
8\3 = 2
8%3 = 0.6666
HTH…
ld go
Slider at 1 -> 1°, 2°, 3°.
Slider at 2 -> 2°, 4°, 6°
Slider at 3, etc.
And when the angle was too much that it surpassed 90 before connecting the 20 points, that line was not created. Maybe using a series instead of a range...mmm
Everything helps, thanks
…
Integer = 0 To 9
val *= 2
lst.Add(val)
Next
Since val is a ValueType, when we assign it to the list we actually put a copy of val into the list. Thus, the list contains the following memory layout:
[0] = 2
[1] = 4
[2] = 8
[3] = 16
[4] = 32
[5] = 64
[6] = 128
[7] = 256
[8] = 512
[9] = 1024
Now let's assume we do the same, but with OnLines:
Dim ln As New OnLine(A, B)
Dim lst As New List(Of OnLine)
For i As Integer = 0 To 9
ln.Transform(xform)
lst.Add(ln)
Next
When we declare ln on line 1, it is assigned an address in memory, say "24 Bell Ave." Then we modify that one line over and over, and keep on adding the same address to lst. Thus, the memory layout of lst is now:
[0] = "24 Bell Ave."
[1] = "24 Bell Ave."
[2] = "24 Bell Ave."
[3] = "24 Bell Ave."
[4] = "24 Bell Ave."
[5] = "24 Bell Ave."
[6] = "24 Bell Ave."
[7] = "24 Bell Ave."
[8] = "24 Bell Ave."
[9] = "24 Bell Ave."
To do this properly, we need to create a unique line for every element in lst:
Dim lst As New List(Of OnLine)
For i As Integer = 0 To 9
Dim ln As New OnLine(A, B)
ln.Transform(xform)
lst.Add(ln)
Next
Now, ln is constructed not just once, but whenever the loop runs. And every time it is constructed, a new piece of memory is reserved for it and a new address is created. So now the list memory layout is:
[0] = "24 Bell Ave."
[1] = "12 Pike St."
[2] = "377 The Pines"
[3] = "3670 Woodland Park Ave."
[4] = "99 Zoo Ln."
[5] = "13a District Rd."
[6] = "2 Penny Lane"
[7] = "10 Broadway"
[8] = "225 Franklin Ave."
[9] = "420 Paper St."
--
David Rutten
david@mcneel.com
Poprad, Slovakia…
Added by David Rutten at 6:26am on September 9, 2010
sequence
Ok, then yes, but still, the next case. We have 20 curves, 0 and 19 are the same. You do 4 sublists of 5 crvs and uses RemDupCrvs. The index 0 and 19 will never be in the same branch (so dont be deleted except if at the end you flatten everything) whereas the comparison of curves with indices 0 and 1 has been calculated as many times as you have repeated that process. But I do not know the reason for the increase in speed actually.…
output will show a tree with 3 branches of 4 integers each that I can pass on to other components. What is the best way to do it?
I have tried creating a tree and using a for loop to do so, but it didn't work.
Thank you for your help.
…