the first area and the first number, the second area and the second number and the third are and the third number. For example, let's assume we have the following areas {65, 15, 20}. The absolute difference between these two sets equals {abs(44-65), abs(39-15), abs(17-20)} == {21, 24, 3}. The sum-total of all these absolute differences is your fitness, i.e. 21+24+3 = 48. This number has to go to zero.
If we enter the results you just got, then the absolute differences look like this: {abs(44-44), abs(39-17), abs(17-39)} == {0, 22, 22}, which results in a fitness of 44. Only an exact match will result in a fitness of zero.
--
David Rutten
david@mcneel.com
Seattle, WA…
Added by David Rutten at 12:44pm on November 13, 2010
lysurface component. After installing the pufferfish2-3.gha, please close Rhino completely one time to avoid potential assembly reference errors with the "Twisted Box" components. Make sure to first remove any other versions of Pufferfish you may have installed. Pufferfish V2.3 works with Rhino 5, Rhino 6, and Rhino Mac. Some components require at least Rhino 5 SR14. Some versions of Rhino 6 Grasshopper have a mesh display issue not related to Pufferfish, if you see a weird mesh, try Recomputing Grasshopper until it goes away. …
etting when I merge the three trees, but what I would like to get is:
essentially a tree with 27 branches, each with a single list of either 11 or 21 points.
{0} (N=11)
{1} (N=11)
...
{10} (N=21)
{11} (N=21)
...
{17} (N=11)
{18) (N=11)
{27} (N=11)
Any help would be greatly appreciated.
All the best,
Matt
…
Added by Matt Schmid at 3:06pm on December 4, 2010
he height from the top of one step to the next, for example, 17 cm.
In the tutorial, the lower face of the first step starts on zero and the upper face is the thickness of the material for example, 5 cm.
how can I set the definition in a way that the lower face of the first step starts at 12 cm, +5 of thickness the upper face would be at 17?
I thank you in advance for your attention,
Hector…
e possible to change the component definition making possible to customize the number of outputs.Now Dispatch moves "true" values to A and "False" values to B
INPUT:
L (List to work on) -> 1, 2, 3, 4, 5, 6, 7, 8
D (Dispatch Pattern) -> True, False
OUTPUT:
A (List) -> 1, 3, 5, 7
B (List) -> 2, 4, 6, 8
Could it be possible/useful to modify it so it could dispatch items to several outputs, like:
INPUT:
L (List to work on) -> 1, 2, 3, 4, 5, 6, 7, 8, 9, 0
D (Dispatch Pattern) -> A, B, C
OUTPUT:
A (List) -> 1, 4, 7, 0
B (List) -> 2, 5, 8
C (List) -> 3, 6, 9
maybe I'm missing something and there's already a component with this function... I have been searching on the forum for half afternoon, but can't find anything about it!
Thank you!…