para poder parametrizarla - Entender cómo se gestionan los datos con Grasshopper - Asociar formulaciones matemáticas a modelos paramétricos - Panelizar y triangular superficies - Parametrizar estructuras sencillas - Saber deformar modelos tridimensionales paramétricamente - Elaboración de algoritmos simples y aplicarlos a modelos tridimensionales - Exportar e importar tablas de datos
El curso será impartido por dos Authorized Rhino Trainers.
También te informamos de que hemos renovado el temario del curso, preparado específica y exclusivamente por nosotros, y que es revisado y ampliado continuamente, gracias a la experiencia de cursos anteriores. El curso tiene un formato intensivo de 18 horas, cuyo horario es: - viernes, de 16 a 20; - sábado, de 10 a 14 y de 16 a 20; - domingo, de 11 a 14 y de 16 a 19.
Si estás interesado en apuntarte, contáctanos en: cursos@frikearq.com…
s than 40% on average.2. 8gb usage is steady at 28% 3. I've been now looking at 2 blank white screen, in both Rhino and Grasshopper for well over 20 min. finally I went for a walk at 10:25am, (its a beautiful day why waste it looking at nonexistent calculations, It would help if there was a timing function in the code that would let me know how long the calculations were going to take, came back 11:25am still no results. Had to Quit Rhino in the Start manager.
I have used all sorts of window programs for well over 25 years. Rhino and Grasshopper are the only 2 programs that I have ever seen that show totally white screens in their operating windows :(
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with 10 ordered curves. These in turn are to be interated in a move slider( 10 vectors).
As I plug these 3 new grafts in the move slider though, these curves all iterated 10 times (100 curves total) instead of being lifted one at a time.
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ay how many valid permutations exist.
But allow me to guesstimate a number for 20 components (no more, no less). Here are my starting assumptions:
Let's say the average input and output parameter count of any component is 2. So we have 20 components, each with 2 inputs and 2 outputs.
There are roughly 35 types of parameter, so the odds of connecting two parameters at random that have the same type are roughly 3%. However there are many conversions defined and often you want a parameter of type A to seed a parameter of type B. So let's say that 10% of random connections are in fact valid. (This assumption ignores the obvious fact that certain parameters (number, point, vector) are far more common than others, so the odds of connecting identical types are actually much higher than 3%)
Now even when data can be shared between two parameters, that doesn't mean that hooking them up will result in a valid operation (let's ignore for the time being that the far majority of combinations that are valid are also bullshit). So let's say that even when we manage to pick two parameters that can communicate, the odds of us ending up with a valid component combo are still only 1 in 2.
We will limit ourselves to only single connections between parameters. At no point will a single parameter seed more than one recipient and at no point will any parameter have more than one source. We do allow for parameters which do not share or receive data.
So let's start by creating the total number of permutations that are possible simply by positioning all 20 components from left to right. This is important because we're not allowed to make wires go from right to left. The left most component can be any one of 20. So we have 20 possible permutations for the first one. Then for each of those we have 19 options to fill the second-left-most slot. 20×19×18×17×...×3×2×1 = 20! ~2.5×1018.
We can now start drawing wires from the output of component #1 to the inputs of any of the other components. We can choose to share no outputs, output #1, output #2 or both with any of the downstream components (19 of them, with two inputs each). That's 2×(19×2) + (19×2)×(19×2-1) ~ 1500 possible connections we can make for the outputs of the first component. The second component is very similar, but it only has 18 possible targets and some of the inputs will already have been used. So now we have 2×(18×2-1) + (18×2-1)×(18×2-1) ~1300. If we very roughly (not to mention very incorrectly, but I'm too tired to do the math properly) extrapolate to the other 18 components where the number of possible connections decreases in a similar fashion thoughout, we end up with a total number of 1500×1300×1140×1007×891×789×697×...×83×51×24×1 which is roughly 6.5×1050. However note that only 10% of these wires connect compatible parameters and only 50% of those will connect compatible components. So the number of valid connections we can make is roughly 3×1049.
All we have to do now is multiply the total number of valid connection per permutation with the total number of possible permutations; 20! × 3×1049 which comes to 7×1067 or 72 unvigintillion as Wolfram|Alpha tells me.
Impressive as these numbers sound, remember that by far the most of these permutations result in utter nonsense. Nonsense that produces a result, but not a meaningful one.
EDIT: This computation is way off, see this response for an improved estimate.
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David Rutten
david@mcneel.com
Poprad, Slovakia…
Added by David Rutten at 12:06pm on March 15, 2013
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I am triangulating this surface. I want to select just the red vertices. As you can note, I just need the inner vertices of this surface. I could do it mannually, but if I want to change the mesh density later, I will have to pick all of them manually again later.
Can someone help me?
Tks
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1#comments
But I seem to be having a problem with this closest to some value thing: values in my list are too small, up too 1 x 10^-30. The closest value I want to search for in that list is 1.25 x 10^-9
But Grasshoppers "find similar" component recognizes all of the values from the list, to be similar to 1.25 x 10^-9, because all of those values are in range from 0.1 to 1 x 10^-30.
Is there a way some kind of tolerance can be made, when it comes to recognizing a similar value?…