e
7. True
8. True <-- this one
9. True
10. False
11. True
12. False
13. True
14. True <-- this one
15. True
16. False
17. True
18. False
19. True
20. True <-- this one
21. True
22. False
23. True
24. False
25. True
26. True <-- this one
27. True
28. False
29. True
30. False
31. True
32. True <-- this one
33. True
Any idea how I can solve this?
Thanks!…
7,8. It would plot on the line of the 20%, 20%, 70%, 80% of the length of the line. I'm not looking for a way to divide the curve by 2 and then by 2,not steps. So I would have two points at 20%. I hope this is clear.
Thanks,
Tom…
rated by "<" symbols. Examples: "2<10", "2<4<10", "Pow(2, 1)<5*Sin(3)<10".
The entered text contains 2 or 3 segments separated by two or more consecutive dots. Examples "2..10", "2..4..10", "Pow(2, 1)....5*Sin(3)..10".
If only two segments are provided, then the initial value will be the same as the minimum value. If a bounds number or a default value is written as a simple number, then the number of decimal places will be harvested. I.e. "2..4..10" is not the same as "2..4..10.00" as the former will result in an integer slider and the latter in a slider with two decimal places.
--
David Rutten
david@mcneel.com
Poprad, Slovakia…
Added by David Rutten at 10:08am on February 15, 2013
re are only few shapes that could be obtained with 10:16 projector.
Here is def, which enables to "design" desired projected shape.
This room doesnt exist.…
the paths.
Structure one (paths = 2)
{1;0;0;0;0}(N=10)
{2;0;0;0;0}(N=10)
Structure two (paths = 2)
{1;0;0;0}(N=10)
{2;0;0;0}(N=10)
If i merge the two lists i don't get a structure with 2 paths:
Structure result af merging (2 paths)
{1}(N=20)
{2}(N=20)
as i had expected, but instead a structure with 4 paths because of the difference in amount of zeroes:
Structure result af merging (4 paths)
{1;0;0;0;0}(N=10)
{2;0;0;0;0}(N=10)
{1;0;0;0}(N=10)
{2;0;0;0}(N=10)
The amount of zeroes changes all the time when working on the definition, so what im asking is if there some way to adress paths with * number of zeroes behind.…
Hi All,Is it possible to re-parameterize this curve or apply percentage values as opposed to the lengths (let's say they are unknown)?i.e. 10% - 20% dash distribution of overall length?
. etc. So it's 80020 which is ~1058. Assuming you're allowed to use the same component more than once.
1058 × 1049 = 10107 total possible algorithms. When talking about big numbers I only have three frames of reference. The distance from us to the edge of the observable universe is roughly 1029 millimeters, the observable universe contains 1080 protons and the volume of the observable universe is roughly 5×10105 cubic nanometers. So you could more or less put a different valid Grasshopper algorithm into every cubic nanometer of this universe.
--
David Rutten
david@mcneel.com
Poprad, Slovakia…
nent outputs with 10 curves each or a single parameter/component output that contains 3 paths of 10 elements?
I'm guessing it's the former. If so, then just place a "graft tree" component after each list, then connect the 3 graft tree components to the join component.…
ll these 12500 points.
Group 1 would represent the point located at 0, 5, 10, 15, 20 etc.
Group 2 - 1, 6, 11, 16, 21 etc.
Group 3 - 2, 7, 12, 17, 22 etc.
Group 4 - 3, 8, 13, 18, 23 etc.
Group 5 - 4, 9, 14, 19, 24 etc.
I can create the pattern but the selection of points are all the points in row 0 and then all the points in row 5 and so on.
I would like the selection of points to start at the bottom left, and sequentially continue to the right and then continue on the 2nd row (left to right & bottom to top). i am hoping the pattern i am trying to achieve is more understood with the quick screen capture I uploaded.
the end goal is to be able to select all the points in the grid that are in each pattern.
Thanks in advance for any guidance with this. …
Added by Alyne Rankin at 6:53am on October 11, 2017