Creating a data tree from another data tree

Hi,

I want to craft a data tree from an existing data tree based on a specific pattern (in this case I wand to do what "Diamond Grid" component does in "Paneling Tools" plug-in.

Let's say we have tree with A,B,C,D as branches and 10 items in each of them. The goal is to have an algorithm that gets {C4} and sends out {C3,D4,C5,B4}. Please have a look at the image attached.

This is something that I can achieve on a tool like Processing, but not able to do in Grasshopper. I would appreciate it if someone give me instructions.

Regards,

Mani

Attachments:

DATA TREE QUESTION.jpg, 1.9 MB

Replies to This Discussion

Permalink Reply by David Rutten on January 19, 2016 at 2:50pm

It's probably easiest to use the RelativeItem component. Unfortunately you'll need one for each of the four points, and there may be issues where the pattern terminates (should it wrap? clip? be jagged?)

Permalink Reply by Mani Kh on January 19, 2016 at 4:07pm

Thanks David.

Where the pattern ends we should have branches with less than 4 items. I guess that would be a "clip".

Permalink Reply by Joseph Oster on January 19, 2016 at 3:22pm

You could look at the problem a little differently and get diamonds the way I did a week ago, using 'Isotrim' to split a surface, then use mid-points of the subsurfaces' edges to make the diamonds:

http://www.grasshopper3d.com/xn/detail/2985220:Comment:1436596

Attachments:

diamonds_along_curve_2016_Jan19a.gh, 23 KB

Permalink Reply by Mani Kh on January 19, 2016 at 4:05pm

Joseph,

Thanks for you comment!

That's a good approach but not enough control when you have a irregular curved surface.

I know that I mentioned Diamond Grid. But this is a question that I have about data structure in general, to create arrays from existing ones based on a specific pattern.

Permalink Reply by Ethan Gross on January 19, 2016 at 4:40pm

I know all the cool kids are using Relative Item, which I highly recommend, but here is another approach - assuming the lists are all of the same length.

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